Django选择不重复字段不生效

1 投票
1 回答
1431 浏览
提问于 2025-04-17 10:02

我有两个模型:

class Team(models.Model):
        """
        Team model for creating a basic team.
        """
        image = ThumbnailerImageField(upload_to=_profile_image_directory(), verbose_name=u'Logo', help_text=u'Uploading a team logo is highly recommended.', blank=True)
        name = models.CharField(verbose_name=u'Team Name', max_length=100)
        school = models.CharField(verbose_name=u'School Name', max_length=100, blank=True)
        city = models.CharField(max_length=100, blank=True)
        state = USStateField(blank=True)
        description = models.CharField(blank=True, max_length=175)
        members = models.ManyToManyField(User, through='TeamMember')
        key = models.CharField(max_length=8, unique=False, blank=True)
        private = models.BooleanField(blank=True)
        twitter = models.CharField(verbose_name=u'Twitter handle', max_length=15, blank=True)
        hashtag = models.CharField(help_text=u'Tweets containing this hashtag will be pulled into your team\'s Twitter feed', max_length=20, blank=True)

        def __unicode__(self):
                return u'%s' % (self.name)

        class Meta:
                verbose_name = u'Team'
                verbose_name_plural = u'Teams'
                unique_together = ('name', 'school', 'state')

class TeamMember(models.Model):
        """
        Team model for connecting users with teams.
        """
        user = models.ForeignKey(User)
        team = models.ForeignKey(Team)
        number = models.PositiveIntegerField(max_length=3, blank=True, null=True)
        position = models.CharField(max_length=100, blank=True)
        start = models.CharField(help_text=u'Year only. Format: 2004', max_length=4, blank=True)
        end = models.CharField(help_text=u'Year only. Leave blank for current team', max_length=4, blank=True)
        created = models.DateTimeField(auto_now_add=True)
        updated = models.DateTimeField(auto_now=True)

我想通过名字搜索当前用户的所有队友,所以我这里有一个查询:

TeamMember.objects.filter(team__members=request.user).filter(user__username__icontains=query).exclude(user=request.user)

这个查询可以正常工作,但如果某个用户在多个相同的团队中,我会多次得到重复的用户。因此,我想在用户字段上使用 DISTINCT 或 GROUP BY,但我尝试的所有方法都没有成功。

我尝试过:

TeamMember.objects.filter(team__members=request.user).filter(user__username__icontains=query).exclude(user=request.user).distinct("user")

这个方法可以工作,但给我的用户信息不够,只返回他们的 ID,因为它被转换成了一个字典:

TeamMember.objects.filter(team__members=request.user).filter(user__username__icontains=query).exclude(user=request.user).values("user").distinct()

有什么想法吗?

1 个回答

2

你的查询返回的是不同的 TeamMember,而不是不同的 user

为了获取不同的 user

user.objects.filter( 
                teammember__team__teammember__user__icontains=query
          ).exclude(user=request.user).distinct()

解释一下:不同的 users 是指那些 teammember 所在的 team,这个 team 和一个包含 queryuser 相关联,所有这些都不包括当前登录的用户。

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