Python中的动态数组和结构体中的结构体

Question

我正在尝试在Python中使用ctypes实现这些C语言的结构体：

struct _rows {
    int cols_count;
    char *cols[];
}

struct _unit {
    int rows_count;
    struct _rows *rows;
}

int my_func(struct _unit *param);

问题是，_rows.cols是一个动态大小的字符指针数组，而_unit.rows是一个动态大小的_rows结构体数组。我该如何在Python中使用ctypes来实现这个呢？

我已经能够定义一个函数，返回一个包含可变数量字符指针的_rows结构体：

def get_row(cols):
    class Row(ctypes.Structure):
        _fields_ = [("cols_count", ctypes.c_int), 
                    ("cols", ctypes.c_char_p * cols)
                   ]

接下来我该怎么做呢？有点不清楚，而且ctypes的文档也没有太大帮助。

Answer 1

我在猜测提问者想要的内容，如果有更简单的方法，请大家给我建议。不过这是我想到的解决方案：

demo.py

import string
from ctypes import Structure,c_int,c_char_p,POINTER,cast,pointer,byref,CDLL

class Row(Structure):
    _fields_ = [('cols_count', c_int), 
                ('cols', POINTER(c_char_p))]
    def __init__(self,cols):
        self.cols_count = cols
        # Allocate an array of character pointers
        pc = (c_char_p * cols)()
        self.cols = cast(pc,POINTER(c_char_p))            

class Unit(Structure):
    _fields_ = [('rows_count', c_int),
                ('rows',POINTER(Row))]
    def __init__(self,rows,cols):
        self.rows_count = rows
        # Allocate an array of Row structures.
        # This does NOT call __init__.
        pr = (Row * rows)()
        # Call init manually with the column size.
        for r in pr:
            r.__init__(cols)
        self.rows = cast(pr,POINTER(Row))

unit = Unit(2,3)

# Stuff some strings ('aaaaa','bbbbb',etc.)
for i in xrange(unit.rows_count):
    for j in xrange(unit.rows[i].cols_count):
        unit.rows[i].cols[j] = string.ascii_lowercase[i*5+j]*5

dll = CDLL('test.dll')
dll.my_func(byref(unit))

test.c

#include <stdio.h>

struct _rows {
    int cols_count;
    char **cols;
};

struct _unit {
    int rows_count;
    struct _rows *rows;
};

__declspec(dllexport) int my_func(struct _unit *param)
{
    int i,j;
    for(i=0;i<param->rows_count;i++)
        for(j=0;j<param->rows[i].cols_count;j++)
            printf("%d,%d = %s\n",i,j,param->rows[i].cols[j]);
    return 0;
}

makefile

这个是用Visual Studio 2010编译的。

test.dll: test.c
    cl /W4 /LD test.c

输出结果

0,0 = aaaaa
0,1 = bbbbb
0,2 = ccccc
1,0 = fffff
1,1 = ggggg
1,2 = hhhhh