带可变参数的Python扩展模块
我正在尝试弄清楚在C扩展模块中,如何让一个函数接受很多(可能还挺多的)参数。
我读到关于PyArg_ParseTuple的内容,似乎你必须知道要接受多少个参数,有些是必需的,有些是可选的,但每个参数都得有自己的变量。我原本希望PyArg_UnpackTuple能处理这个问题,但当我尝试用错的方法时,它似乎只给我带来了总线错误。
举个例子,看看下面这段Python代码,可能想把它做成一个扩展模块(用C语言)。
def hypot(*vals):
if len(vals) !=1 :
return math.sqrt(sum((v ** 2 for v in vals)))
else:
return math.sqrt(sum((v ** 2 for v in vals[0])))
这个函数可以用任意数量的参数调用,像这样:hypot(3,4,5)
、hypot([3,4,5])
,还有hypot(*[3,4,5])
,这三种调用方式都会得到相同的结果。
我C语言函数的开头看起来是这样的:
static PyObject *hypot_tb(PyObject *self, PyObject *args) {
// lots of code
// PyArg_ParseTuple or PyArg_UnpackTuple
}
非常感谢yasar11732。这里给下一个人提供一个完整的工作扩展模块(_toolboxmodule.c),它可以接受任意数量的整数参数,并返回一个由这些参数组成的列表(名字起得不太好)。这是个玩具示例,但说明了需要做的事情。
#include <Python.h>
int ParseArguments(long arr[],Py_ssize_t size, PyObject *args) {
/* Get arbitrary number of positive numbers from Py_Tuple */
Py_ssize_t i;
PyObject *temp_p, *temp_p2;
for (i=0;i<size;i++) {
temp_p = PyTuple_GetItem(args,i);
if(temp_p == NULL) {return NULL;}
/* Check if temp_p is numeric */
if (PyNumber_Check(temp_p) != 1) {
PyErr_SetString(PyExc_TypeError,"Non-numeric argument.");
return NULL;
}
/* Convert number to python long and than C unsigned long */
temp_p2 = PyNumber_Long(temp_p);
arr[i] = PyLong_AsUnsignedLong(temp_p2);
Py_DECREF(temp_p2);
}
return 1;
}
static PyObject *hypot_tb(PyObject *self, PyObject *args)
{
Py_ssize_t TupleSize = PyTuple_Size(args);
long *nums = malloc(TupleSize * sizeof(unsigned long));
PyObject *list_out;
int i;
if(!TupleSize) {
if(!PyErr_Occurred())
PyErr_SetString(PyExc_TypeError,"You must supply at least one argument.");
return NULL;
}
if (!(ParseArguments(nums, TupleSize, args)) {
free(nums);
return NULL;
}
list_out = PyList_New(TupleSize);
for(i=0;i<TupleSize;i++)
PyList_SET_ITEM(list_out, i, PyInt_FromLong(nums[i]));
free(nums);
return (PyObject *)list_out;
}
static PyMethodDef toolbox_methods[] = {
{ "hypot", (PyCFunction)hypot_tb, METH_VARARGS,
"Add docs here\n"},
// NULL terminate Python looking at the object
{ NULL, NULL, 0, NULL }
};
PyMODINIT_FUNC init_toolbox(void) {
Py_InitModule3("_toolbox", toolbox_methods,
"toolbox module");
}
在Python中,它是:
>>> import _toolbox
>>> _toolbox.hypot(*range(4, 10))
[4, 5, 6, 7, 8, 9]
2 个回答
0
谢谢@yasar,模板非常感谢你。而接下来的这个改编可能有点过于简单了——不过简单总是好的,对吧?
ctst.c:
/*
* https://realpython.com/build-python-c-extension-module
*
* gcc -O2 -fPIC -c ctst.c $(python3-config --includes)
* gcc -shared ctst.o -o ctst.so
*/
#include <Python.h>
static PyObject *
cargs(PyObject *self, PyObject *args)
{
Py_ssize_t n_args = PyTuple_Size(args);
PyObject * lst = PyList_New(0);
for (int i = 0; i < n_args; i++) {
PyObject * item = PyTuple_GetItem(args, i);
// play with items one at a time ...
// yes, malloc is needed to play with all
// items outside this loop
PyList_Append(lst, item);
}
return lst;
}
static PyMethodDef MyCtstMethods[] = {
{"cargs", fcrgs, METH_VARARGS,
"toss a bunch of Python vars into a C function, return the list (maybe) modified"},
{NULL, NULL, 0, NULL}
};
static struct PyModuleDef ctst = {
PyModuleDef_HEAD_INIT, "ctst", "testing C calls", -1, MyCtstMethods
};
PyMODINIT_FUNC
PyInit_ctst(void)
{
return PyModule_Create(&ctst);
}
tst.py:
import ctst
print('test0 (null):', ctst.cargs())
print('test1 (ints):', ctst.cargs(1, 2, 3))
print('test2 (mix) :', ctst.cargs(1, 2, 3, 'hi'))
print('test3 (flt) :', ctst.cargs(0.1234))
print('test4 (lst) :', ctst.cargs(['a', 'b', 'c']))
11
我之前用过类似的东西。可能这段代码写得不好,因为我不是很有经验的C语言程序员,但对我来说是有效的。这里的关键是,*args其实就是一个Python的元组,你可以对它做任何在Python元组上能做的事情。你可以查看一下这个链接了解更多信息:http://docs.python.org/c-api/tuple.html。
int
ParseArguments(unsigned long arr[],Py_ssize_t size, PyObject *args) {
/* Get arbitrary number of positive numbers from Py_Tuple */
Py_ssize_t i;
PyObject *temp_p, *temp_p2;
for (i=0;i<size;i++) {
temp_p = PyTuple_GetItem(args,i);
if(temp_p == NULL) {return NULL;}
/* Check if temp_p is numeric */
if (PyNumber_Check(temp_p) != 1) {
PyErr_SetString(PyExc_TypeError,"Non-numeric argument.");
return NULL;
}
/* Convert number to python long and than C unsigned long */
temp_p2 = PyNumber_Long(temp_p);
arr[i] = PyLong_AsUnsignedLong(temp_p2);
Py_DECREF(temp_p2);
if (arr[i] == 0) {
PyErr_SetString(PyExc_ValueError,"Zero doesn't allowed as argument.");
return NULL;
}
if (PyErr_Occurred()) {return NULL; }
}
return 1;
}
我调用这个函数的方式是这样的:
static PyObject *
function_name_was_here(PyObject *self, PyObject *args)
{
Py_ssize_t TupleSize = PyTuple_Size(args);
Py_ssize_t i;
struct bigcouples *temp = malloc(sizeof(struct bigcouples));
unsigned long current;
if(!TupleSize) {
if(!PyErr_Occurred())
PyErr_SetString(PyExc_TypeError,"You must supply at least one argument.");
free(temp);
return NULL;
}
unsigned long *nums = malloc(TupleSize * sizeof(unsigned long));
if(!ParseArguments(nums, TupleSize, args)){
/* Make a cleanup and than return null*/
return null;
}