mp3文件的时长

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6 回答
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提问于 2025-04-11 09:23

有没有什么简单的方法可以知道一个mp3文件的长度(以秒为单位),而不使用外部库? (如果能提供Python代码就更好了)

6 个回答

8

简单地说,就是用Python解析MP3的二进制数据来计算一些东西。

这听起来有点难。我不太懂Python,不过我有一些从我之前写的另一个程序中整理出来的代码。

注意:这段代码是用C++写的(抱歉,这是我能提供的)。而且,这段代码只能处理恒定比特率的MPEG 1 音频层3文件。大多数情况下应该可以用,但我不能保证在所有情况下都能正常工作。希望这段代码能满足你的需求,也希望把它改写成Python比从头开始写要简单。

// determines the duration, in seconds, of an MP3;
// assumes MPEG 1 (not 2 or 2.5) Audio Layer 3 (not 1 or 2)
// constant bit rate (not variable)

#include <iostream>
#include <fstream>
#include <cstdlib>

using namespace std;

//Bitrates, assuming MPEG 1 Audio Layer 3
const int bitrates[16] = {
         0,  32000,  40000,  48000,  56000,  64000,  80000,   96000,
    112000, 128000, 160000, 192000, 224000, 256000, 320000,       0
  };


//Intel processors are little-endian;
//search Google or see: http://en.wikipedia.org/wiki/Endian
int reverse(int i)
{
    int toReturn = 0;
    toReturn |= ((i & 0x000000FF) << 24);
    toReturn |= ((i & 0x0000FF00) << 8);
    toReturn |= ((i & 0x00FF0000) >> 8);
    toReturn |= ((i & 0xFF000000) >> 24);
    return toReturn;
}

//In short, data in ID3v2 tags are stored as
//"syncsafe integers". This is so the tag info
//isn't mistaken for audio data, and attempted to
//be "played". For more info, have fun Googling it.
int syncsafe(int i)
{
 int toReturn = 0;
 toReturn |= ((i & 0x7F000000) >> 24);
 toReturn |= ((i & 0x007F0000) >>  9);
 toReturn |= ((i & 0x00007F00) <<  6);
 toReturn |= ((i & 0x0000007F) << 21);
 return toReturn;     
}

//How much room does ID3 version 1 tag info
//take up at the end of this file (if any)?
int id3v1size(ifstream& infile)
{
   streampos savePos = infile.tellg(); 

   //get to 128 bytes from file end
   infile.seekg(0, ios::end);
   streampos length = infile.tellg() - (streampos)128;
   infile.seekg(length);

   int size;
   char buffer[3] = {0};
   infile.read(buffer, 3);
   if( buffer[0] == 'T' && buffer[1] == 'A' && buffer[2] == 'G' )
     size = 128; //found tag data
   else
     size = 0; //nothing there

   infile.seekg(savePos);

   return size;

}

//how much room does ID3 version 2 tag info
//take up at the beginning of this file (if any)
int id3v2size(ifstream& infile)
{
   streampos savePos = infile.tellg(); 
   infile.seekg(0, ios::beg);

   char buffer[6] = {0};
   infile.read(buffer, 6);
   if( buffer[0] != 'I' || buffer[1] != 'D' || buffer[2] != '3' )
   {   
       //no tag data
       infile.seekg(savePos);
       return 0;
   }

   int size = 0;
   infile.read(reinterpret_cast<char*>(&size), sizeof(size));
   size = syncsafe(size);

   infile.seekg(savePos);
   //"size" doesn't include the 10 byte ID3v2 header
   return size + 10;
}

int main(int argCount, char* argValues[])
{
  //you'll have to change this
  ifstream infile("C:/Music/Bush - Comedown.mp3", ios::binary);

  if(!infile.is_open())
  {
   infile.close();
   cout << "Error opening file" << endl;
   system("PAUSE");
   return 0;
  }

  //determine beginning and end of primary frame data (not ID3 tags)
  infile.seekg(0, ios::end);
  streampos dataEnd = infile.tellg();

  infile.seekg(0, ios::beg);
  streampos dataBegin = 0;

  dataEnd -= id3v1size(infile);
  dataBegin += id3v2size(infile);

  infile.seekg(dataBegin,ios::beg);

  //determine bitrate based on header for first frame of audio data
  int headerBytes = 0;
  infile.read(reinterpret_cast<char*>(&headerBytes),sizeof(headerBytes));

  headerBytes = reverse(headerBytes);
  int bitrate = bitrates[(int)((headerBytes >> 12) & 0xF)];

  //calculate duration, in seconds
  int duration = (dataEnd - dataBegin)/(bitrate/8);

  infile.close();

  //print duration in minutes : seconds
  cout << duration/60 << ":" << duration%60 << endl;

  system("PAUSE");
  return 0;
}
11

为了帮助谷歌的关注者,这里有一些额外的外部库:

参考资料:

(把这个做成一个维基,方便其他人添加内容)。

还有一些库:.net: naudio,java: jlayer,c: libmad

谢谢!

26

你可以使用 pymad 这个库。虽然它是一个外部库,但不要被“自己发明的东西最好”这种想法所影响。你有什么特别的理由不想使用外部库吗?

import mad

mf = mad.MadFile("foo.mp3")
track_length_in_milliseconds = mf.total_time()    

你可以在 这里 找到相关信息。

--

如果你真的不想使用外部库,可以看看 这里,看看他是怎么做的。不过要注意:这会比较复杂。

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