XML:回溯父元素
我在找一个解决方案,关于在Python中处理XML的问题。虽然spectrum不是根元素,但为了这个例子,我们假设它是根元素。
<spectrum index="2" id="controller=0 scan=3" defaultArrayLength="485">
<cvParam cvRef="MS" accession="MS:1000511" name="ms level" value="2"/>
<cvParam cvRef="MS" accession="MS:1000580" name="MSn spectrum" value=""/>
<cvParam cvRef="MS" accession="MS:1000127" name="centroid mass spectrum" value=""/>
<precursorList count="1">
<precursor spectrumRef="controller=0 scan=2">
<isolationWindow>
<cvParam cvRef="MS" accession="MS:1000040" name="m/z" value="810.78999999999996"/>
<cvParam cvRef="MS" accession="MS:1000023" name="isolation width" value="2"/>
</isolationWindow>
<selectedIonList count="1">
<selectedIon>
<cvParam cvRef="MS" accession="MS:1000040" name="m/z" value="810.78999999999996"/>
</selectedIon>
</selectedIonList>
<activation>
<cvParam cvRef="MS" accession="MS:1000133" name="collision-induced dissociation" value=""/>
<cvParam cvRef="MS" accession="MS:1000045" name="collision energy" value="35"/>
</activation>
</precursor>
</precursorList>
<binaryDataArrayList count="2">
<binaryDataArray encodedLength="5176">
<cvParam cvRef="MS" accession="MS:1000523" name="64-bit float" value=""/>
<cvParam cvRef="MS" accession="MS:1000576" name="no compression" value=""/>
<cvParam cvRef="MS" accession="MS:1000514" name="m/z array" value="" unitCvRef="MS" unitAccession="MS:1000040" unitName="m/z"/>
<binary>AAAAYHHsbEAAAADg3yptQAAAAECt7G1AAAAAAN8JbkAAAAAA.......hLJ==</binary>
</binaryDataArray>
<binaryDataArray encodedLength="2588">
<cvParam cvRef="MS" accession="MS:1000521" name="32-bit float" value=""/>
<cvParam cvRef="MS" accession="MS:1000576" name="no compression" value=""/>
<cvParam cvRef="MS" accession="MS:1000515" name="intensity array" value=""/>
<binary>ZFzUQWmVo0FH/o9BRfUyQg+xjUOzkZdC5k66QWk6HUSpqyZCsV1NQ......uH=</binary>
</binaryDataArray>
</binaryDataArrayList>
</spectrum>
我想要做的是在这个树形结构中找到所有的selectedIon元素,并追溯到它的父元素spectrum。如果找到了selectedIon元素,那么
SelectedIon的信息是:
质量:810.78999999999996
Spectra Info: ------------- index=2 id=controller=0 scan=3 length=485 General Info ------------ ms level=2 Msn spectrum= - centriod mass spectrum=- ..................... And all the cvParam name and value as above. Binary ------ m/z array = AAAAYHHsbEAAAADg3yptQAAAAECt7G1AAAA.....== intensity array = ZFzUQWmVo0FH/o9BRfUyQg+xjUOzkZdC5k66Q....5C77=
我到目前为止尝试过的:
import xml.etree.ElementTree as ET
tree=ET.parse('file.mzml')
NS="{http://psi.hupo.org/ms/mzml}"
filesource=tree.findall('.//'+NS+'selectedIon') # Will get all selectedIon element from the tree
那么我该如何追溯到spectrum元素或其子元素,以提取上面提到的相关信息呢?
我该如何成功呢?
2 个回答
0
如果这个问题现在还存在,你可以试试 pymzML,这是一个用来处理mzML文件的Python工具。
要打印所有MS2光谱的信息,其实非常简单:
import pymzml
msrun = pymzml.run.Reader("your-file.mzML")
for spectrum in msrun:
if spectrum['ms level'] == 2:
# spectrum is a dict, so you can just print it
print(spectrum)
(声明:我也是这个工具的作者之一)
1
XPath可以让你访问一个祖先元素:使用“ancestor::spectrum”可以找到你所在的
from lxml import etree
tree = etree.XML('file.mzml')
NS = "{http://psi.hupo.org/ms/mzml}"
filesource = tree.findall('.//'+NS+'selectedIon')
spectrum = filesource.xpath('ancestor::spectrum')[0]
(我觉得是这样,但没测试过...)
更新:实际上能工作的代码:
from lxml import etree
tree = etree.parse('foo.xml')
for el in tree.findall(".//selectedIon"):
for top in el.xpath("ancestor::spectrum"):
print top