我为什么无法调用这个列表？

Question

我正在尝试从一个模块中导入一个列表，但出现了这个错误：

错误追踪（最近的调用在前）： 文件 "main.py"，第 8 行，在 words_list = hangman_words.word_list() 类型错误：'list' 对象不可调用

这是我的代码：

#Step 5
import hangman_words
import hangman_art
import random

#TODO-1: - Update the word list to use the 'word_list' from hangman_words.py
#Delete this line: word_list = ["ardvark", "baboon", "camel"]
words_list = hangman_words.word_list()
chosen_word = random.choice(words_list)
word_length = len(chosen_word)

end_of_game = False
lives = 6

#TODO-3: - Import the logo from hangman_art.py and print it at the start of the game.
print(hangman_art.logo)
#Testing code
print(f'Pssst, the solution is {chosen_word}.')

#Create blanks
display = []
for _ in range(word_length):
    display += "_"

while not end_of_game:
    guess = input("Guess a letter: ").lower()

    #TODO-4: - If the user has entered a letter they've already guessed, print the letter and let them know.
    if guess in display:
      print(f"You've already guessed {guess}")
    #Check guessed letter
    for position in range(word_length):
        letter = chosen_word[position]
        print(f"Current position: {position}\n Current letter: {letter}\n Guessed letter: {guess}")
        if letter == guess:
            display[position] = letter

    #Check if user is wrong.
    if guess not in chosen_word:
        #TODO-5: - If the letter is not in the chosen_word, print out the letter and let them know it's not in the word.
        print(f"You guessed {guess}, that is not in the word. You lose a (1) life")
        lives -= 1
        if lives == 0:
            end_of_game = True
            print("You lose.")

    #Join all the elements in the list and turn it into a String.
    print(f"{' '.join(display)}")

    #Check if user has got all letters.
    if "_" not in display:
        end_of_game = True
        print("You win.")

    #TODO-2: - Import the stages from hangman_art.py and make this error go away.
    print(hangman_art.stages[lives])

我试着把它放在一个变量里，正如你在我的代码中看到的，但结果还是出现了完全相同的错误。

Answer 1

我觉得你可能是把hangman_words.word_list()当成一个函数来用，而实际上它是一个列表。你只需要去掉括号，就可以这样写：

words_list = hangman_words.word_list

希望这能帮到你，谢谢！

Answer 2

看起来 hangman_words.word_list 是一个 list（列表）。在Python中，列表是不能像函数那样被调用的。

替代方案 1：

如果你的目标是获取指向 hangman_words 中提到的列表的引用，你可以这样做：

在 hangman_words.py 文件中：

word_list = ['all', 'words', 'you', 'have']

在你的脚本中：

from hangman_words import word_list

print(word_list)

结果是： ['all', 'words', 'you', 'have']

替代方案 2：

如果你需要对你的列表进行某些操作，或者想确保不改变原始列表，你可以使用一个函数来获取原始列表的副本。可以这样做：

在 hangman_words.py 文件中：

import copy
__word_list = ['all', 'words', 'you', 'have']

def get_word_list():
   return copy.deep_copy(__word_list)

在你的脚本中：

from hangman_words import get_word_list

print(get_word_list())

结果是： ['all', 'words', 'you', 'have']