django 从管理界面添加数据时: TypeError at admin/... unicode对象不可调用

Question

我在使用管理界面保存以下模型时遇到了一个错误：

models.py

class Answer(models.Model):
a = models.TextField(primary_key=True)
gloss = models.TextField(blank=True)  
clean = models.TextField(blank=True)  
count = models.IntegerField(blank=True)
p = models.IntegerField(blank=True)    
def __unicode__(self):
    return u"%s" % self.a    
class Meta:                                       
    db_table = u'answers'                         

这是在管理界面上显示的错误信息：

Environment:


Request Method: POST
Request URL: http://localhost:8000/admin/emotions/answer/add/

Django Version: 1.4 pre-alpha SVN-16322
Python Version: 2.6.2
Installed Applications:
['django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.sites',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'django.contrib.admin',
 'emo20qBrowser.emotions']
Installed Middleware:
('django.middleware.common.CommonMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware')


Traceback:
File "/home/abe/bin/django-trunk/django/core/handlers/base.py" in get_response
  111.                         response = callback(request, *callback_args,     **callback_kwargs)
File "/home/abe/bin/django-trunk/django/contrib/admin/options.py" in wrapper
  316.                 return self.admin_site.admin_view(view)(*args, **kwargs)
File "/home/abe/bin/django-trunk/django/utils/decorators.py" in _wrapped_view
  91.                     response = view_func(request, *args, **kwargs)
File "/home/abe/bin/django-trunk/django/views/decorators/cache.py" in _wrapped_view_func
  77.         response = view_func(request, *args, **kwargs)
File "/home/abe/bin/django-trunk/django/contrib/admin/sites.py" in inner
  196.             return view(request, *args, **kwargs)
File "/home/abe/bin/django-trunk/django/utils/decorators.py" in _wrapper
  25.             return bound_func(*args, **kwargs)
File "/home/abe/bin/django-trunk/django/utils/decorators.py" in _wrapped_view
  91.                     response = view_func(request, *args, **kwargs)
File "/home/abe/bin/django-trunk/django/utils/decorators.py" in bound_func
  21.                 return func(self, *args2, **kwargs2)
File "/home/abe/bin/django-trunk/django/db/transaction.py" in inner
  211.                 return func(*args, **kwargs)
File "/home/abe/bin/django-trunk/django/contrib/admin/options.py" in add_view
  871.             if form.is_valid():
File "/home/abe/bin/django-trunk/django/forms/forms.py" in is_valid
  121.         return self.is_bound and not bool(self.errors)
File "/home/abe/bin/django-trunk/django/forms/forms.py" in _get_errors
  112.             self.full_clean()
File "/home/abe/bin/django-trunk/django/forms/forms.py" in full_clean
  269.         self._post_clean()
File "/home/abe/bin/django-trunk/django/forms/models.py" in _post_clean
  331.             self.instance.clean()

Exception Type: TypeError at /admin/emotions/answer/add/
Exception Value: 'unicode' object is not callable

Answer 1

好的，我想我搞明白了……我在用一个叫“clean”的变量/列。Django的管理界面也有一个叫“clean()”的方法，它用来做一些验证。看起来这两个名字冲突了，所以我把变量改成了“cleaned”。为了确保它知道用哪个数据库字段（因为我在用一个旧的数据库），我还加了一个db_column选项：

cleaned = models.TextField(blank=True,db_column="clean")

如果早知道“clean”在Django里是个保留字就好了，不过至少我只在这Django的事上浪费了半天时间，理论上它应该能让数据库操作更简单。老实说，我今天早上才开始学Django，如果我能在StackOverflow上找到答案，解决起来就简单多了。

如果有人知道更好的处理方法，请告诉我……