如何在Django Tastypie中返回相关模型的数据?

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提问于 2025-04-17 02:16

我该如何把另一个模型的信息引入进来呢?

我有两个模型,分别是 ArticleArticleBody

Article 里包含主要信息,而 ArticleBody 里则包含了一系列的正文和图片信息。

class Article(models.Model):
    author = models.ForeignKey(User)
    title = models.CharField(max_length=100)
    excerpt = models.CharField(max_length=140, null=True, blank=True, help_text='A description no longer than 140 characters that explains what the article is about, important for SEO')
    category = models.ManyToManyField(Category)
    date_published = models.DateTimeField()
    slug = models.SlugField(null=True)
    status = models.CharField(choices=STATUS, max_length=2, default='DR')
    tags = TagField(default='', null=True, blank=True, help_text='Just add a comma between the tags i.e. "My very important name, Hunting, Scope, Rifle"')
    source_name = models.CharField(default='', blank=True, null=True, help_text='Outdoor Magazine', max_length=100)
    source_url = models.URLField(verify_exists=False, max_length=200, null=True, blank=True, help_text='http://www.source.com/2011/01/long-name/')

class ArticleBody(ImageModel):
    article = models.ForeignKey(Article)
    body = models.TextField(verbose_name='', blank=True, null=True)
    image = models.ImageField(storage=cloudfiles_storage, upload_to='articles', default='avatar-blank.jpg', verbose_name='', blank=True, null=True)
    caption = models.CharField(max_length=80, null=True, blank=True)

在我的 api resources.py 文件里,我正在尝试把 ArticleBody 的信息引入到我的 NewsResource 中……

这就是我目前的进展。

class NewsBodyResource(ModelResource):
    class Meta:
        queryset = ArticleBody.objects.all()
        resource_name = 'article_body'

class NewsResource(ModelResource):

    class Meta:
        queryset = Article.objects.filter(status='PU', date_published__lt=datetime.datetime.now).order_by('-date_published')
        resource_name = 'news'

那么,正确的 TastyPIE 方法是什么呢?我该如何修改才能把 ArticleBody 的循环信息引入到我的 NewsResource 中?

1 个回答

5
class NewsBodyResource(ModelResource):
    class Meta:
        queryset = ArticleBody.objects.all()
        resource_name = 'article_body'

class NewsResource(ModelResource):
    newsbodies = fields.ToManyField('yourapp.api.resources.NewsBodyResource', 'articlebody_set', full=True)

    class Meta:
        queryset = Article.objects.filter(status='PU', date_published__lt=datetime.datetime.now).order_by('-date_published')
        resource_name = 'news'

ToManyField的参数分别代表以下内容:

  1. 资源的导入路径,这个路径是相对于项目的,用来表示一组数据

  2. 如果这个字段在父模型上,就写字段的名字;如果在子模型上,就写这个字段的related_name属性

  3. 是否要把每个子项的完整数据嵌入到信息中(选择True),还是只放每个子项的链接(选择False)

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