从Python字典中删除值
我有一个这样的 Python 字典:
{'1' : {'1': {'A' : 34, 'B' : 23, 'C' : nan, 'D': inf, ...} ....} ....}
对于每个“字母”键,我需要计算一些东西,但我得到的值有时是无穷大(inf)或不是一个数字(nan),我需要把它们去掉。我该怎么做呢?
我第一次尝试是“剪掉”这些值,也就是只保留在 0 到 1000 之间的值,但这样做后,我得到的字典里全是空值:
{'1' : {'1': {'A' : 34, 'B' : 23, 'C' : {}, 'D': {}, ...} ....} ....}
也许还有更好的解决办法,请帮帮我!!!!
这是我代码的一部分,(Q 和 L 是其他字典,里面有我需要计算的信息):
for e in L.keys():
dR[e] = {}
for i in L[e].keys():
dR[e][i] = {}
for l, ivalue in L[e][i].iteritems():
for j in Q[e].keys():
dR[e][i][j] = {}
for q, jvalue in Q[e][j].iteritems():
deltaR = DeltaR(ivalue, jvalue) #this is a function that I create previously
if (0 < deltaR < 100):
dR[e][i][j] = deltaR
2 个回答
1
你可以使用 del 这个语句来删除字典中的某个项目。比如说:
del dct['1']['1']['C']
0
我在这里试着猜测一下,但你可能有几种不同的方法可以做到这一点。一个方法是先计算出值,然后再决定是否真的想把它放进字典里。
d = {}
for letter in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':
# I don't actually know how you're calculating values
# and it kind of doesn't matter
value = calculate(letter)
if value in (inf, nan):
continue
d[letter] = value
我把字典简化了,只关注你数据中实际使用字母作为键的部分,因为你没有提供太多背景信息。话虽如此,我可能会选择第一个建议,除非有特别的理由不这样做。
for e in L.keys():
dR[e] = {}
for i in L[e].keys():
dR[e][i] = {}
for l, ivalue in L[e][i].iteritems():
for j in Q[e].keys():
#dR[e][i][j] = {} # What's up with this? If you don't want an empty dict,
# just don't create one.
for q, jvalue in Q[e][j].iteritems():
deltaR = DeltaR(ivalue, jvalue) #this is a function that I create previously
if (0 < deltaR < 100):
dR[e][i][j] = deltaR
if dR[e][i][j] in (nan, inf):
del dR[e][i][j]