在Pyramid中使用FormEncode的ForEach和嵌套变量创建表单项数组
我正在使用Pyramid和FormEncode来创建和验证地址列表。我用的是pyramid_simpleform,并且查看了这个教程 http://jimmyg.org/blog/2007/multiple-checkboxes-with-formencode.html 以及之前的一个问题 Pylons FormEncode with an array of form elements,但我仍然遇到了一些问题。我的结构目前是这样的:
模式:
from formencode import Schema, validators, ForEach, NestedVariables
class AddressSchema(Schema):
allow_extra_fields = False
addresses = validators.String(not_empty=True)
class JobSchema(Schema):
filter_extra_fields = True
allow_extra_fields = True
pre_validators = [NestedVariables()]
job_name = validators.MinLength(5, not_empty=True)
comments = validators.MinLength(5, not_empty=False)
addresses = ForEach(AddressSchema())
模板:
${renderer.errorlist("addresses")}
${renderer.errorlist("job_name")}
<p><label for="job_name">Job name: </label>${renderer.text("job_name", size=30)}</p>
% for a in range(1, initial_number_of_address_fields):
<p><label for="addresses-${a}">Address: </label>${renderer.textarea("addresses-" + str(a), cols=39, rows=6)}</p>
% endfor
${renderer.submit("submit", "Submit")}
视图:
@view_config(route_name='add_addresses', renderer="add_addresses.mak")
def add_addresses(request):
from myproject.forms import JobSchema
from myproject.models import Job
from formencode import htmlfill, variabledecode, ForEach
initial_number_of_address_fields = 5
form = Form(request, schema=JobSchema(), variable_decode=False)
renderer = FormRenderer(form)
# if the form has been submitted
if 'submit' in request.POST:
if form.validate(): # uses validation specified in forms.py
# automatically bind to provided form
obj = form.bind(Job()) # no exisiting id provided, so a new document is created
# add some additional values
obj.__setattr__("last_updated_on", datetime.date.today().strftime('%Y/%m/%d'))
#save
obj.save()
return HTTPFound(location="/")
return {
'title':'Add addresses',
'initial_number_of_address_fields': initial_number_of_address_fields,
'renderer': renderer
}
我收到了一些实际的验证错误,像这样:
{'addresses': u'Missing value'}
但是即使是填写正确的值也会出现错误:
输入必须是字典类型(而不是:u'dgfgfd')
如果我把 variable_decode
改为 True
(在表单变量设置中),我就完全不再收到任何错误了。我觉得我应该以某种方式使用 variable_decode
,但我不太确定该怎么做。请问我该如何正确验证这些值呢?
1 个回答
0
我在2009年写过一篇博客,内容和这个用法类似,可能对你有帮助:
http://www.domenkozar.com/2009/07/22/advanced-formencode-usage/