使用`python的etree.iterparse()`解析大xml文件时出错,代码中是否存在逻辑错误?

2 投票
2 回答
3052 浏览
提问于 2025-04-16 17:47

我想要解析一个很大的XML文件。这个文件里的记录,比如说,长得像这样。总的来说,文件的结构是这样的:

<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE dblp SYSTEM "dblp.dtd">
<dblp>
    record_1
    ...
    record_n
</dblp>

我写了一些代码,目的是从这个文件中选取一些记录。

当我运行这段代码时(整个过程差不多要50分钟,包括把数据存入MySQL数据库),我发现有一条记录似乎有将近一百万个作者。这肯定是错的。我还特意查看了文件,确保里面没有错误。这篇论文只有5或6个作者,所以dblp.xml文件没有问题。所以我猜是我的代码逻辑出了错。但我就是找不到问题出在哪里。也许有人能告诉我,错误在哪里?

代码在这一行停止了:if len(auth) > 2000

import sys
import MySQLdb
from lxml import etree


elements = ['article', 'inproceedings', 'proceedings', 'book', 'incollection']
tags = ["author", "title", "booktitle", "year", "journal"]


def fast_iter(context, cursor):
    mydict = {} # represents a paper with all its tags.
    auth = [] # a list of authors who have written the paper "together".
    counter = 0 # counts the papers

    for event, elem in context:
        if elem.tag in elements and event == "start":
            mydict["element"] = elem.tag
            mydict["mdate"] = elem.get("mdate")
            mydict["key"] = elem.get("key")

        elif elem.tag == "title" and elem.text != None:
            mydict["title"] = elem.text
        elif elem.tag == "booktitle" and elem.text != None:
            mydict["booktitle"] = elem.text
        elif elem.tag == "year" and elem.text != None:
            mydict["year"] = elem.text
        elif elem.tag == "journal" and elem.text != None:
            mydict["journal"] = elem.text
        elif elem.tag == "author" and elem.text != None:
            auth.append(elem.text)
        elif event == "end" and elem.tag in elements:
            counter += 1
            print counter
            #populate_database(mydict, auth, cursor)
            mydict.clear()
            auth = []
            if mydict or auth:
                sys.exit("Program aborted because auth or mydict was not deleted properly!")
        if len(auth) > 200: # There are up to ~150 authors per paper. 
            sys.exit("auth: It seams there is a paper which has too many authors.!")
        if len(mydict) > 50: # A paper can have much metadata.
            sys.exit("mydict: It seams there is a paper which has too many tags.")

        elem.clear()
        while elem.getprevious() is not None:
            del elem.getparent()[0]
    del context


def main():
        cursor = connectToDatabase()
        cursor.execute("""SET NAMES utf8""")

        context = etree.iterparse(PATH_TO_XML, dtd_validation=True, events=("start", "end"))
        fast_iter(context, cursor)

        cursor.close()


if __name__ == '__main__':
    main()

编辑:

我在写这个函数的时候完全搞错了。我犯了一个大错误,没注意到在跳过一些不需要的记录时,结果把一些需要的记录也搞混了。在文件的某个点上,我连续跳过了将近一百万条记录,导致后面的需要的记录被搞得很乱。

在John和Paul的帮助下,我成功地重写了我的代码。现在它正在解析,看起来效果不错。如果还有什么意外的错误没有解决,我会再回来报告。否则,非常感谢大家的帮助!我真的很感激!

def fast_iter2(context, cursor):
    elements = set([
        'article', 'inproceedings', 'proceedings', 'book', 'incollection',
        'phdthesis', "mastersthesis", "www"
        ])
    childElements = set(["title", "booktitle", "year", "journal", "ee"])

    paper = {} # represents a paper with all its tags.
    authors = []   # a list of authors who have written the paper "together".
    paperCounter = 0
    for event, element in context:
        tag = element.tag
        if tag in childElements:
            if element.text:
                paper[tag] = element.text
                # print tag, paper[tag]
        elif tag == "author":
            if element.text:
                authors.append(element.text)
                # print "AUTHOR:", authors[-1]
        elif tag in elements:
            paper["element"] = tag
            paper["mdate"] = element.get("mdate")
            paper["dblpkey"] = element.get("key")
            # print tag, element.get("mdate"), element.get("key"), event
            if paper["element"] in ['phdthesis', "mastersthesis", "www"]:
                pass
            else:
                populate_database(paper, authors, cursor)
            paperCounter += 1
            print paperCounter
            paper = {}
            authors = []
            # if paperCounter == 100:
            #     break
            element.clear()
            while element.getprevious() is not None:
                del element.getparent()[0]
    del context

2 个回答

3

在你检测到元素中标签开始和结束的代码块里,加上打印语句,这样可以确保你正确地检测到这些标签。我怀疑你可能因为某种原因没有执行到清空作者列表的那段代码。

试着把这段代码注释掉(或者至少把它移到“结束”处理的部分):

    elem.clear()
    while elem.getprevious() is not None:
        del elem.getparent()[0]

在你遍历XML的时候,Python应该会自动帮你清空这些元素。“del context”这一行其实是多余的。让引用计数来帮你处理这些事情就可以了。

3

请消除一个混淆点:你并没有明确说明你展示的代码是否在“计数超过2000”的测试中出错。如果没有问题,那可能是你没有展示的数据库更新代码出了问题。

如果确实出错了:

(1) 把限制从2000降低到合理的值(比如auth大约20,mydict正好7)。

(2) 当出错时,使用print repr(mydict); print; print repr(auth)来打印内容,并与文件中的内容进行比较。

另外,使用iterparse()时,elem.text在“开始”事件发生时并不一定已经被解析。为了节省一些运行时间,你应该在“结束”事件发生时再访问elem.text。实际上,似乎没有必要在“开始”事件时做任何事情。此外,你定义了一个列表tags,但从未使用过。你函数的开头可以写得更简洁:

def fast_iter(context, cursor):
    mydict = {} # represents a paper with all its tags.
    auth = [] # a list of authors who have written the paper "together".
    counter = 0 # counts the papers
    tagset1 = set(['article', 'inproceedings', 'proceedings', 'book', 'incollection'])
    tagset2 = set(["title", "booktitle", "year", "journal"])
    for event, elem in context:
        tag = elem.tag
        if tag in tagset2:
            if elem.text:
                mydict[tag] = elem.text
        elif tag == "author":
            if elem.text:
                auth.append(elem.text)
        elif tag in tagset1:
            counter += 1
            print counter
            mydict["element"] = tag
            mydict["mdate"] = elem.get("mdate")
            mydict["dblpkey"] = elem.get("key")
            #populate_database(mydict, auth, cursor)
            mydict.clear() # Why not just do mydict = {} ??
            auth = []
            # etc etc

别忘了修正iterparse()的调用,去掉events参数。

我还相当确定elem.clear()应该只在事件为“结束”时执行,并且只在tag in tagset1时执行。请仔细阅读相关文档。在“开始”事件中进行清理可能会损坏你的树结构。

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