装饰递归函数
我写了一个装饰器,可以用来计算某个函数的执行时间。这个装饰器对任何函数都能很好地工作,但对递归函数就不行了。
装饰器代码:
def tictoc(repeats=3, loops=1):
def t(func):
from functools import partial, wraps
import timeit
@wraps(func)
def timer(*args, **kargs):
elapsed = timeit.repeat(partial(func, *args, **kargs), repeat = repeats, number=loops)
mine = min(elapsed)
print "%s finished in %.5fs (%d loops, %d times) with %.5fs per loop" % (func.__name__, mine, loops, repeats, mine/loops)
return timer
return t
这个递归函数是基本的斐波那契算法。
@tictoc()
def fib(i):
return ( 0 if i == 0 else
1 if i == 1 else
fib(i-1) + fib(i-2) )
fib(15)
程序出现了以下错误:
fib finished in 0.00000s (1 loops, 3 times) with 0.00000s per loop
fib finished in 0.00000s (1 loops, 3 times) with 0.00000s per loop
fib finished in 0.00000s (1 loops, 3 times) with 0.00000s per loop
Traceback (most recent call last):
File "decor.py", line 61, in <module>
[fib(x) for x in range(1,50)]
File "/home/grout/Dropbox/Python/tictoc.py", line 7, in timer
elapsed = timeit.repeat(partial(func, *args, **kargs), repeat = repeats, number=loops)
File "/usr/lib/python2.7/timeit.py", line 233, in repeat
return Timer(stmt, setup, timer).repeat(repeat, number)
File "/usr/lib/python2.7/timeit.py", line 221, in repeat
t = self.timeit(number)
File "/usr/lib/python2.7/timeit.py", line 194, in timeit
timing = self.inner(it, self.timer)
File "/usr/lib/python2.7/timeit.py", line 100, in inner
_func()
File "decor.py", line 59, in fib
fib(i-1) + fib(i-2) )
TypeError: unsupported operand type(s) for +: 'NoneType' and 'NoneType'
我不明白的是,为什么装饰器能执行几次后就失败了。希望能得到一些帮助。
2 个回答
6
你写的装饰器函数没有返回任何东西。所以虽然 fib
应该返回一个整数,但你包裹后的 fib
实际上返回的是 None
。它能正常工作几次是因为有一些递归调用没有检查 fib
的结果,但当需要结果的时候(比如要把两个结果加在一起),就会出现错误。
0
我想我决定就用这个了
def tictoc(func, repeats=3, loops=100, *args, **kargs):
elapsed = timeit.repeat(lambda: func(*args, **kargs), repeat = repeats, number = loops)
mine = min(elapsed)
return "%s finished in %.5fs (%s loops, repeated %s times): %.5fs best time per loop" %(func.__name__, mine, loops, repeats, mine/loops)