打开shelve文件

Question

我正在尝试在“my.db”这个数据库里查找一个“键”。我做了以下操作：

import shelve
db_file = os.path.join(self.path_data, 'my_directory', 'my.db')
s = shelve.open(db_file)
val = s["key"]

但是我遇到了这个错误：

 /opt/Python-2.4.3/lib/python2.4/shelve.py in open(filename='/path_here/dir/netmhcpan.db', flag='c', protocol=None, writeback=False, binary=None)
 /opt/Python-2.4.3/lib/python2.4/shelve.py in __init__(self=<DbfilenameShelf instance>, filename='/path_here/dir/netmhcpan.db', flag='c', protocol=None, writeback=False, binary=None)
 /opt/Python-2.4.3/lib/python2.4/anydbm.py in open(file='/path_here/dir/netmhcpan.db', flag='c', mode=438)
......
ImportError: No module named _bsddb
  args = ('No module named _bsddb',) 

希望能得到一些帮助来解决这个问题。谢谢。

Answer 1

安装 db4-devel 这类的东西，然后重新编译 Python。