urllib2.HTTPError: HTTP 错误 500:内部服务器错误

3 投票
1 回答
19802 浏览
提问于 2025-04-16 15:33
  if data.find('!exploits') != -1:
     nick = data.split('!')[ 0 ].replace(':','')
     results = api.exploitdb.search(arg)
     sck.send('PRIVMSG ' + chan + " :" + ' Results found: %s' % results['total'] + '\r\n')
     for exploit in results['matches'][:5]:
              sck.send('PRIVMSG ' + chan + "" + '%s:' % (exploit['description'] + '\r\n')) 

这个小脚本是用来在 exploit-db 上搜索已知的漏洞,但是当我在 IRC 中使用它时,似乎不太好使,但单独运行时没问题。

这里的“单独”是指只运行这个:

from shodan import WebAPI

SHODAN_API_KEY = "MY API KEY"
api = WebAPI(SHODAN_API_KEY)

results = api.exploitdb.search('PHP')

print 'Results found: %s' % results['total']
for exploit in results['matches'][:5]:
        print '%s:' % (exploit['description'])

这个运行得很好,但我想把它和 IRC 一起用。

可是我遇到了这个错误:

Traceback (most recent call last):
  File "C:\Users\Rabia\Documents\scripts\client.py", line 232, in <module>
    results = api.exploitdb.search(arg)
  File "C:\Python26\lib\site-packages\shodan\api.py", line 63, in search
    return self.parent._request('exploitdb/search', dict(q=query, **kwargs))
  File "C:\Python26\lib\site-packages\shodan\api.py", line 116, in _request
    data = urlopen(self.base_url + function + '?' + urlencode(params)).read()
  File "C:\Python26\lib\urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "C:\Python26\lib\urllib2.py", line 397, in open
    response = meth(req, response)
  File "C:\Python26\lib\urllib2.py", line 510, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python26\lib\urllib2.py", line 435, in error
    return self._call_chain(*args)
  File "C:\Python26\lib\urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "C:\Python26\lib\urllib2.py", line 518, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 500: Internal Server Error

1 个回答

2

你的代码应该没问题。

这可能是服务器的问题。内部错误——服务器因为一些意外情况无法处理请求。

你可以查看一下返回状态,了解它的意思。

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