Django中的语法错误

1 投票
1 回答
758 浏览
提问于 2025-04-16 15:10

这个urls.py文件里为什么会出现语法错误呢?

错误提示是:

syntax error at Line 27[(r'^xd_receiver\.html$',.....] in ursl.py.

我搞不清楚问题出在哪里。

  urlpatterns = patterns('',
        # Example:
        # (r'^universityDB/', include('universityDB.foo.urls')),

        # Uncomment the admin/doc line below to enable admin documentation:
        # (r'^admin/doc/', include('django.contrib.admindocs.urls')),
        # Uncomment the next line to enable the admin:
        (r'^admin/', include(admin.site.urls)),
        (r'^registrationForm/$','universityDB.universityDetails.views.registrationForm'),
        (r'^userDetails/$','universityDB.universityDetails.views.userDetails'),
        (r'^login/$','universityDB.universityDetails.views.login'),
        (r'^userCreated/$','universityDB.universityDetails.views.userCreated'),
        (r'^forgotPassword/$','universityDB.universityDetails.views.forgotPassword'),
        (r'^passwordRecovery/$','universityDB.universityDetails.views.passwordRecovery'),     
        (r'^accounts/profile', 'universityDB.universityDetails.views.profile'),   
        (r'^xd_receiver\.html$', direct_to_template, {'template': 'xd_receiver.html'}, name='xd_receiver'),   
        (r'^login_facebook_connect/$', 'login_facebook_connect', name='facebook_connect_ajax'),

    )

1 个回答

5

如果你想给你的网址起个名字,你需要使用 url(...) 这个函数,也就是说:

url(r'^xd_receiver\.html$', direct_to_template, {'template': 'xd_receiver.html'}, name='xd_receiver')

…而不是:

(r'^xd_receiver\.html$', direct_to_template, {'template': 'xd_receiver.html'}, name='xd_receiver')

撰写回答