使用词汇列表计算Levenshtein距离

Question

首先，我想说我在Python方面还是个新手。我正在尝试计算很多单词列表之间的Levenshtein距离。到目前为止，我已经成功写出了计算两个单词之间距离的代码，但在处理列表时遇到了一些问题。我有两个单词列表，像这样一行一个：

carlos
stiv
peter

我想用Levenshtein距离来做相似性比较。有没有人能告诉我怎么加载这些列表，然后用一个函数来计算距离呢？

我会很感激的！

这是我只针对两个字符串的代码：

#!/usr/bin/env python
# -*- coding=utf-8 -*-

def lev_dist(source, target):
    if source == target:
        return 0

#words = open(test_file.txt,'r').read().split();

    # Prepare matrix
    slen, tlen = len(source), len(target)
    dist = [[0 for i in range(tlen+1)] for x in range(slen+1)]
    for i in xrange(slen+1):
        dist[i][0] = i
    for j in xrange(tlen+1):
        dist[0][j] = j

    # Counting distance
    for i in xrange(slen):
        for j in xrange(tlen):
            cost = 0 if source[i] == target[j] else 1
            dist[i+1][j+1] = min(
                            dist[i][j+1] + 1,   # deletion
                            dist[i+1][j] + 1,   # insertion
                            dist[i][j] + cost   # substitution
                        )
    return dist[-1][-1]

if __name__ == '__main__':
    import sys
    if len(sys.argv) != 3:
        print 'Usage: You have to enter a source_word and a target_word'
        sys.exit(-1)
    source, target = sys.argv[1], sys.argv[2]
    print lev_dist(source, target)

Answer 1

别重复造轮子：

http://pypi.python.org/pypi/python-Levenshtein/

Answer 2

我终于在朋友的帮助下把代码搞定了 :)

你可以计算两个字符串之间的相似度，叫做Levenshtein距离，然后把这个距离和第二个列表里的每个单词进行比较。只需要修改脚本的最后一行，也就是把原来的print(list1[0], list2[i])改成这样，就可以把列表1中的第一个单词和列表2中的每个单词进行比较了。

谢谢大家！

#!/usr/bin/env python
# -*- coding=utf-8 -*-

import codecs

def lev_dist(source, target):
    if source == target:
        return 0


    # Prepare a matrix
    slen, tlen = len(source), len(target)
    dist = [[0 for i in range(tlen+1)] for x in range(slen+1)]
    for i in range(slen+1):
        dist[i][0] = i
    for j in range(tlen+1):
        dist[0][j] = j

    # Counting distance, here is my function
    for i in range(slen):
        for j in range(tlen):
            cost = 0 if source[i] == target[j] else 1
            dist[i+1][j+1] = min(
                            dist[i][j+1] + 1,   # deletion
                            dist[i+1][j] + 1,   # insertion
                            dist[i][j] + cost   # substitution
                        )
    return dist[-1][-1]

# load words from a file into a list
def loadWords(file):
    list = [] # create an empty list to hold the file contents
    file_contents = codecs.open(file, "r", "utf-8") # open the file
    for line in file_contents: # loop over the lines in the file
        line = line.strip() # strip the line breaks and any extra spaces
        list.append(line) # append the word to the list
    return list

if __name__ == '__main__':
    import sys
    if len(sys.argv) != 3:
        print 'Usage: You have to enter a source_word and a target_word'
        sys.exit(-1)
    source, target = sys.argv[1], sys.argv[2]

    # create two lists, one of each file by calling the loadWords() function on the file
    list1 = loadWords(source)
    list2 = loadWords(target)

    # now you have two lists; each file has to have the words you are comparing on the same lines
    # now call you lev_distance function on each pair from those lists

    for i in range(0, len(list1)): # so now you are looping over a range of numbers, not lines
        print lev_dist(list1[0], list2[i])


#    print lev_dist(source, target)