Python SocketServer 连接时出错

Question

我正在用Python 3.1的socketserver模块运行一个Python服务器。每次客户端成功连接时，我的服务器都会收到一个错误。以下是我的代码：

import socket
import socketserver
import string
import struct

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
    def handle(self):
        message = self.request.recv(1024).decode().strip()
        print("%s sent: '%s'" % (self.address,message))

if __name__ == "__main__":
    server = socketserver.TCPServer(("localhost",22085), Server)
    print("Socket created. . .")
    print("Awaiting connections. . .")
    server.serve_forever()

这是我遇到的错误：

----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 49669)
----------------------------------------
Traceback (most recent call last):
  File "C:\Python31\lib\socketserver.py", line 281, in _handle_request_noblock
    self.process_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 307, in process_request
    self.finish_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 320, in finish_request
    self.RequestHandlerClass(request, client_address, self)
TypeError: __init__() takes exactly 1 positional argument (4 given)

我注意到这个错误有点奇怪，因为它第二行提到的端口和我使用的端口不一样。我不太确定这个错误是什么...

谢谢大家的帮助。

Answer 1

差不多十年后，我遇到了同样的问题。（Python 3.9）

多亏了上面那个被投票的答案作为参考，我发现自定义的请求处理器需要接收三个参数，所以我必须重写一个带有三个参数的 __init__ 方法，像下面这样来解决错误。

class ServerRequestHandler(socketserver.BaseRequestHandler):
    def __init__(self, request, client_addr, server):
                # Custom initialisation code here....
                super().__init__(request, client_addr, server)

Answer 2

试着调用一下父类的 __init__ 方法：

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
        super(Server,self).__init__()                  # Init your base class