sys.excepthook在导入模块中不起作用
我正在设计一个Python程序,目的是记录所有未处理的异常,使用的是日志模块。我通过使用sys.excepthook这个函数来覆盖默认的异常处理方式。我发现如果我直接从命令行运行这个程序,它工作得很好,但如果我尝试导入这个文件,就不行了。看起来sys.excepthook函数对日志模块并不了解。下面是一个例子:
#! /usr/bin/env python2.7
import logging, sys
logger = logging.getLogger()
logger.setLevel(logging.DEBUG)
logger.addHandler(logging.FileHandler("test.log"))
print "outside of exception handler: logger = %s" % logger
def handleException(excType, excValue, traceback):
#global logger # this function doesn't work whether or not I include this line
print "inside exception handler: logger = %s" % logger
logger.error("Uncaught exception", exc_info=(excType, excValue, traceback))
sys.excepthook = handleException
logger.debug("starting")
asdf # create an exception
当我从命令行运行这个程序(./loggingTest.py
)时,一切正常。异常会被记录下来,我看到这样的输出:
outside of exception handler: logger = <logging.RootLogger object at 0x7f2022eab950>
inside exception handler: logger = <logging.RootLogger object at 0x7f2022eab950>
但是,如果我启动Python解释器并尝试导入这个文件(import loggingTest
),它就表现得很奇怪。异常没有被记录下来,我看到的是这样的:
outside of exception handler: logger = <logging.RootLogger object at 0x7f8ab04f3ad0>
inside exception handler: logger = None
Error in sys.excepthook:
Traceback (most recent call last):
File "loggingTest.py", line 13, in handleException
logger.error("Uncaught exception", exc_info=(excType, excValue, traceback))
AttributeError: 'NoneType' object has no attribute 'error'
Original exception was:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "loggingTest.py", line 18, in <module>
asdf # create an exception
NameError: name 'asdf' is not defined
我可能可以通过在sys.excepthook里面再次导入日志模块来解决这个问题,但我还是很好奇:为什么会这样呢?
2 个回答
2
我无法重现你遇到的错误,即使它发生在 exhook.py
文件里。这个文件的内容是:
#! /usr/bin/env python2.7
import logging, sys, traceback as tb
logger = logging.getLogger()
logger.setLevel(logging.DEBUG)
logger.addHandler(logging.FileHandler("test.log"))
print "outside of exception handler: logger = %s" % logger
def handleException(excType, excValue, traceback):
#global logger # this function doesn't work whether or not I include this line
tb.print_exception(excType, excValue, traceback)
print "inside exception handler: logger = %s" % logger
logger.error("Uncaught exception", exc_info=(excType, excValue, traceback))
sys.excepthook = handleException
raise Exception
然后:
Python 2.7 (r27:82525, Jul 4 2010, 09:01:59) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> import exhook
outside of exception handler: logger = <logging.RootLogger object at 0x02AB0A70>
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "exhook.py", line 18, in <module>
raise Exception
Exception inside exception handler: logger = <logging.RootLogger object at 0x02AB0A70>
它运行得很好。你这边能正常工作吗?
4
我在Python的错误追踪系统上报告了这个问题,认为它是一个bug。到目前为止,有人回复说在Python 2.7和2.7.1之间确实有变化,他认为这是正常的行为。他还建议可以用下面的方式来记录所有的异常:
def handleException(excType, excValue, traceback, logger=logger):
logger.error("Uncaught exception", exc_info=(excType, excValue, traceback))
sys.excepthook = handleException