Python无法发送请求

Question

我在使用我的oauth库（Django socialauth）连接Twitter时，遇到了一个“CannotSendRequest”的错误。

Traceback:
File "/Library/Python/2.6/site-packages/django/core/handlers/base.py" in get_response
100.                     response = callback(request, *callback_args, **callback_kwargs)
File "/Users/me/webfaction/project/socialauth/views.py" in twitter_login
94.     request_token = twitter.fetch_request_token(callback=request.build_absolute_uri(reverse('socialauth_twitter_login_done')))
File "/Users/me/webfaction/project/socialauth/lib/oauthtwitter2.py" in fetch_request_token
50.         return oauth.OAuthToken.from_string(oauth_response(oauth_request))
File "/Users/me/webfaction/project/socialauth/lib/oauthtwitter2.py" in oauth_response
33.     connection().request(req.http_method, req.to_url())
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/httplib.py" in   request
914.             self._send_request(method, url, body, headers)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/httplib.py" in _send_request
931.         self.putrequest(method, url, **skips)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/httplib.py" in putrequest
818.             raise CannotSendRequest()

Exception Type: CannotSendRequest at /accounts/twitter_login/
Exception Value: 

这是我创建HTTP连接的地方。

def connection():
    try: 
        return connection._connection
    except AttributeError:
        connection._connection = httplib.HTTPSConnection(TWITTER_URL)
    return connection._connection

def oauth_response(req):
    connection().request(req.http_method, req.to_url())
    return connection().getresponse().read()

我在StackOverflow上搜索过，找到了这些链接，但我还是不太确定怎么去实现解决方案。我尝试过但没有成功。任何帮助都非常感谢。

httplib在WSGI中出现CannotSendRequest错误

当我在Python中使用httplib进行OAUTH时，总是会遇到“CannotSendRequest”错误

Answer 1

你提到的那篇帖子说这个错误发生在你重用那些已经出错的连接时，而这些连接还没有到达获取响应的阶段。

确实，当你执行 connection.request("GET", "/") 两次时，会出现这个错误。

建议的解决办法是每次都重新创建连接。你想这样做吗？我对这个问题没有个人看法，你只是问我如何实现那些帖子里的内容。

如果是这样的话，去掉你的 connection() 函数，然后总是执行

connection = httplib.HTTPSConnection(TWITTER_URL)
connection.request(req.http_method, req.to_url())
response = connection.getresponse().read()
connection.close()
return response