为什么在字典中存储SFTP对象时Paramiko会引发EOFError()?

7 投票
3 回答
26179 浏览
提问于 2025-04-16 13:54

我在写一个应用程序时遇到了一些麻烦,这个程序是用来通过SSH下载和上传文件的。现在的问题是,我可以顺利下载文件,但当我尝试把文件上传到另一个服务器时,就会出现EOFError()的错误。我查看了paramiko\sftp.py中的_write_all()函数,发现这个错误似乎是因为它无法将数据写入流中?我对网络编程没有经验,所以如果有人能告诉我它到底在做什么,我会非常感激。

我写了一个简化版的函数来处理我的连接,ssh().runCommand()展示了我的应用程序中上传失败的情况,而simpleTest()则展示了sftp put是如何成功的,但我看不出runCommand()和simpleTest()之间有什么不同,除了我的SFTP对象存储方式不同。一个是存储在字典里,另一个是单独存储。如果字典是问题所在,那下载文件应该也会失败,但事实并非如此。

有没有人知道可能导致这种情况的原因,或者能推荐另一种管理连接的方式,如果现在的方式有问题的话?

我使用的是Python 2.7和Paramiko 1.7.6。我在Linux和Windows上测试了这段代码,结果都是一样的。

编辑:现在包含了代码。

import os
import paramiko

class ManageSSH:
     """Manages ssh connections."""
    def __init__(self):
        self.hosts = {"testbox": ['testbox', 'test', 'test']}
        self.sshConnections = {}
        self.sftpConnections = {}
        self.localfile = "C:\\testfile"
        self.remotefile = "/tmp/tempfile"
        self.fetchedfile = "C:\\tempdl"

    def ssh(self):
        """Manages ssh connections."""
        for host in self.hosts.keys():
            try:
                self.sshConnections[host]
                print "ssh connection is already open for %s" % host
            except KeyError, e:         # if no ssh connection for the host exists then open one
                # open ssh connection
                ssh = paramiko.SSHClient()
                ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
                ssh.connect(self.hosts[host][0], 22, self.hosts[host][1], self.hosts[host][2])
                self.sshConnections[host] = ssh
                print "ssh connection to %s opened" % host
            try:
                self.sftpConnections[host]
                print "sftp connection is already open for %s" % host
            except KeyError, e:
                # open sftp connection
                ssh = paramiko.SSHClient()
                ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
                ssh.connect(self.hosts[host][0], 22, self.hosts[host][1], self.hosts[host][2])
                self.sftpConnections[host] = ssh.open_sftp()
                print "sftp connection to %s opened" % host

    def runCommand(self):
        """run commands and return output"""
        for host in self.hosts:
            command = "if [ -d /tmp ]; then echo -n 1; else echo -n 0; fi"
            stdin, stdout, stderr = self.sshConnections[host].exec_command(command)
            print "%s executed on %s" % (command, host)
            print "returned %s" % stdout.read()
            self.sftpConnections.get(self.remotefile, self.fetchedfile)
            print "downloaded %s from %s" % (self.remotefile, host)
            self.sftpConnections[host].put(self.localfile, self.remotefile)
            print "uploaded %s to %s" % (self.localfile, host)
            self.sftpConnections[host].close()
            self.sshConnections[host].close()

    def simpleTest(self):
        host = "testbox"
        ssh = paramiko.SSHClient()
        ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
        ssh.connect(host, 22, 'test', 'test')
        sftp = ssh.open_sftp()
        print "sftp connection to %s opened" % host
        sftp.get(self.remotefile, self.fetchedfile)
        print "downloaded %s from %s" % (self.localfile, host)
        sftp.put(self.localfile, self.remotefile)
        print "uploaded %s to %s" % (self.localfile, host)
        sftp.close()

if __name__ == "__main__":
    test = ManageSSH()
    print "running test that works"
    test.simpleTest()
    print "running test that fails"
    test.ssh()
    test.runCommand()

输出:

running test that works
sftp connection to testbox opened
downloaded C:\testfile from testbox
uploaded C:\testfile to testbox
running test that fails
ssh connection to testbox opened
sftp connection to testbox opened
if [ -d /tmp ]; then echo -n 1; else echo -n 0; fi executed on testbox
returned 1
downloaded /tmp/tempfile from testbox
Traceback (most recent call last):
  File "paramikotest.py", line 71, in <module>
    test.runCommand()
  File "paramikotest.py", line 47, in runCommand
    self.sftpConnections[host].put(self.localfile, self.remotefile)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 561, in put

    fr = self.file(remotepath, 'wb')
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 245, in open
    t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 627, in _request
    num = self._async_request(type(None), t, *arg)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 649, in _async_request
    self._send_packet(t, str(msg))
  File "C:\Python27\lib\site-packages\paramiko\sftp.py", line 172, in _send_packet
    self._write_all(out)
  File "C:\Python27\lib\site-packages\paramiko\sftp.py", line 138, in _write_all

    raise EOFError()
EOFError

3 个回答

0

在看了你的修改后,我觉得问题出在这里

stdin, stdout, stderr = self.sshConnections[host].exec_command(command)

这一行显然是断开了FTP的连接

已编辑

2

我理解的是,当你用ssh=SSHClient()这行代码时,你是在创建一个SSHClient对象。接着,使用sftp=ssh.open_sftp()这行代码,你又创建了一个sftp对象。虽然你只想用sftp,但你把ssh存储在一个本地变量里,这个变量之后会被垃圾回收(gc)。但是,如果ssh被垃圾回收了,sftp就会神奇地停止工作。我也不知道为什么,但建议你在sftp存在的时候,把ssh保留着。

7

我解决了我的问题。其实我应该使用Paramiko.Transport,然后用 paramiko.SFTPClient.from_transport(t) 来创建 SFTPClient,而不是直接用 SSHClient()open_sftp() 方法。

下面的代码可以正常工作:

t = paramiko.Transport((host, 22))  
t.connect(username=username, password=password)  
sftp = paramiko.SFTPClient.from_transport(t)

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