Django:模型外键和选择框小部件
我有两个模型,分别是 Worker
(工人)和 Position
(职位)。当我添加一个新工人时,应该有一个下拉框,里面列出 Position
模型中的所有职位。
我尝试使用 Select
组件,但 Django 报错说 没有这样的属性
。
模型
# Position model
class Position(models.Model):
p_name = models.CharField(max_length = 40, unique = True, verbose_name = 'Position')
p_salary = models.IntegerField(max_length = 11, verbose_name = 'Salary')
fields = ('p_name', 'p_salary')
# Worker model
class Worker(models.Model):
w_name = models.CharField(max_length = 40, verbose_name = 'Name')
w_lastname = models.CharField(max_length = 40, verbose_name = 'Lastname')
w_position = models.ForeignKey(to = Position, to_field = 'p_name', verbose_name = 'Position')
w_dept = models.ForeignKey(to = Department, to_field = 'd_name' verbose_name = 'Department')
表单
class WorkerForm(ModelForm):
class Meta:
model = Worker
widgets = {
'w_name' : TextInput(attrs = {'class': 'e name'}),
'w_lastame' : TextInput(attrs = {'class': 'e lastname'}),
'w_position': Select(attrs = {'class': 'e position'}),
'w_dept' : Select(attrs = {'class': 'e department'}),
}
在 admin.py 中的定义
class WorkerAdmin(admin.ModelAdmin):
form = WorkerForm
list_display = ('w_name', 'w_lastname', 'w_position', 'w_dept')
出现了什么问题?如何根据外键让下拉框显示出来?
Sultan
1 个回答
1
你可以试着在表单里面重新声明这个字段(记得用和模型里一样的名字),然后在里面设置小部件和属性吗?