在Django EmailMessage中传递元组作为'To'参数时出错

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2 回答
1082 浏览
提问于 2025-04-16 10:57

我在尝试发送电子邮件时遇到了一个错误,具体是在给“收件人”参数传递一组电子邮件地址时出现的问题。

> TypeError: sequence item 0: expected
> string, tuple found

我查看了Django的文档,关于EmailMessage类,上面说这样做应该是没问题的。有没有人能给点建议,看看可能出什么问题了?

我构建EmailMessage对象的方式是这样的:

spam = EmailMessage("Some title - %s \"%s\"" % (subject, task.name), message,
                                "%s <%s>" % (user.get_full_name(), user.email), settings.MAIL_LIST)
spam.content_subtype = "html"
spam.send()

还有

settings.MAIL_LIST = ["foo@bar.com", "foo2@bar.com", "foo3@bar.com"]

部分错误追踪信息:

> File "/myClass/Mail.py", line 217, in
> contact_owner
>     spam.send()
> 
>   File
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py",
> line 281, in send
>     return self.get_connection(fail_silently).send_messages([self])
> 
>   File
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py",
> line 185, in send_messages
>     sent = self._send(message)
> 
>   File
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py",
> line 199, in _send
>     email_message.message().as_string())
> 
>   File
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py",
> line 253, in message
>     msg['To'] = ', '.join(self.to)
> 
> TypeError: sequence item 0: expected
> string, tuple found

2 个回答

0

发送HTML邮件的示例

from django.core.mail import EmailMultiAlternatives
from django.utils.html import strip_tags

subject = render_to_string('cart/email/order_subject.txt',c)
html_body = t.render(Context(c))
text_body = strip_tags(html_body)

msg = EmailMultiAlternatives(subject, text_body, None, sc.settings['email_order'].split(','))
msg.attach_alternative(html_body, "text/html")
msg.send()
0

这其实不是个问题,因为我上面提供的信息是错误的。我的错误基本上就是错误信息所描述的那样。我把一串字符串形式的电子邮件地址传给了需要一组元组的代码。

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