如何让cx-oracle将查询结果绑定到字典而非元组？

Question

这是我的代码。我想找到一种方法，让查询的结果以字典的形式返回，而不是以元组的形式返回。看起来cx_oracle支持这种方式，文档中有提到“绑定”的部分。不过我还搞不清楚具体是怎么操作的。

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    result = curs.fetchall()
    for row in result:
        print row[13] #CATEGORY field order
        print row['CATEGORY'] # <- I want this to work ('CATEGORY' is the name of a field in the 'sometable' table)
    curs.close()

Answer 1

这里有个简单粗暴的方法。如果你有更好的办法，欢迎分享。

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    fieldNumber = 0
    fieldNames={}
    for desc in curs.description:
        fieldNames[desc[0]]=fieldNumber
        fieldNumber+=1
    result = curs.fetchall()
    for row in result:
        print str(row[fieldNames['CATEGORY']])
    curs.close()

Answer 2

绑定变量（Bindvars）用于执行查询，比如：

• 通过名称（给定命名参数）

  cursor = self.db.cursor()
  cursor.execute("SELECT bookName, author from books where Id=:bookId" , bookId="155881")
  print cursor.bindnames()
  

这会输出：['BOOKID']

• 通过位置，给定一个值的列表

  cursor = self.db.cursor()
  cursor.prepare("insert into books (bookId,title,author,price) values(:1, :2, :3, :4)")
  cursor.executemany(None, listOfbookwhichAreTuppleOf4Field )
  

为了得到你想要的结果，你可以尝试这样的方式：

def connect():  
    dsn = cx_Oracle.makedsn("host", 1521, "sid")
    orcl = cx_Oracle.connect('scott/tiger@' + dsn)
    curs = orcl.cursor()
    sql = "select * from sometable"
    curs.execute(sql)
    desc = [d[0] for d in curs.description]
    result = [dict(zip(desc,line)) for line in curs]
    curs.close()