在不使用轮廓的情况下,从x,y,z数据集在3D绘图中使用matplotlib颜色
我实在搞不懂怎么才能得到和这个链接一样的结果。
这个链接可以生成有颜色的3D图,而我如果用同样的方法,但用我自己的x、y、z数据集,就只显示一种颜色。
我想问题可能出在我生成z数据的方式上。
无论如何,我用的是这个:
from mpl_toolkits.mplot3d import Axes3D
from matplotlib.mlab import griddata
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import matplotlib.pyplot as plt
import numpy as np
import sys
def xyz_ret(file):
f = open(file, 'r')
xyz = []
for i in f:
ret = i.replace('\n','')
xyz.append(map(float,(ret.split('\t'))))
xyz = np.array(xyz)
return xyz[:,0],xyz[:,1],xyz[:,2]
x,y,z = xyz_ret('300.txt')
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
xi = np.linspace(min(x), max(x))
yi = np.linspace(min(y), max(y))
X, Y = np.meshgrid(xi, yi)
Z = griddata(x, y, z, xi, yi)
surf = ax.plot_surface(X, Y, Z, rstride=6, cstride=6, cmap=cm.jet,
linewidth=0)
ax.set_zlim3d(min(z), max(z))
ax.w_zaxis.set_major_locator(LinearLocator(10))
ax.w_zaxis.set_major_formatter(FormatStrFormatter('%.03f'))
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
数据集:
-2187.99902 9380.009151 0.0209
-2187.00111 2474.994061 0.022
-10755.98931 6119.598968 0.0296
-5781.347693 609.427388 0.0301
-8761.562524 1942.391853 0.0285
-5695.576244 1894.624701 0.0251
-3801.215106 1096.153308 0.0257
-1616.821487 2452.940102 0.0182
-5790.547537 2975.622971 0.022
-8095.18467 4074.330871 0.0208
-9997.367785 2771.330212 0.0264
-10547.5635 4397.127096 0.0251
-5781.706776 3984.545588 0.0191
-3346.855289 4347.670408 0.0172
-918.639762 4518.515925 0.0142
-892.428381 5850.710005 0.0143
-5844.499993 6516.904257 0.0204
-10877.96951 6015.755723 0.0265
-10813.37291 7704.306099 0.0302
-7991.878303 7733.626264 0.0223
-5861.073574 8725.943697 0.0217
-3188.107715 6997.19893 0.0206
-897.427629 7474.426336 0.0188
-1388.841321 8786.642046 0.0194
-3370.72325 8825.154803 0.0225
-8561.226722 8851.111988 0.0285
-10275.58972 8849.798032 0.0341
-5853.645621 10113.77051 0.0255
-8101.002878 10754.8429 0.0332
-5765.080546 11378.95524 0.0299
-3081.969839 10549.46676 0.0242
结果只显示一种颜色。而且注意,颜色条上没有刻度。
你能告诉我我的问题出在哪里吗?
3 个回答
2
读取文本数据最简单的方法是使用 genfromtxt:
data = np.genfromtxt('300.txt')
x = data[:,0]
y = data[:,1]
z = data[:,2]
这里不需要用到 sys
。
17
我觉得在填充“非连续”的表面时(使用griddata),可能会遇到问题。
代码:
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
import matplotlib.pyplot as plt
from matplotlib.mlab import griddata
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
data = np.genfromtxt('300.txt')
x = data[:,0]
y = data[:,1]
z = data[:,2]
xi = np.linspace(min(x), max(x))
yi = np.linspace(min(y), max(y))
X, Y = np.meshgrid(xi, yi)
Z = griddata(x, y, z, xi, yi)
surf = ax.plot_surface(X, Y, Z, rstride=5, cstride=5, cmap=cm.jet,
linewidth=1, antialiased=True)
ax.set_zlim3d(np.min(Z), np.max(Z))
fig.colorbar(surf)
plt.show()
请注意,如果你把上面的表面看作一个矩形区域 (xi x yi)
,那么这段代码是可以正常工作的。换句话说,如果你把不规则的边缘“切掉”,就没问题了。
xi = np.linspace(-4000, -9000)
yi = np.linspace(4000, 9000)