SQLAlchemy 声明式一对多未定义错误
我正在尝试用SQLAlchemy的声明式ORM来定义一个一对多的关系,并且想让这个例子正常工作,但我遇到了一个错误,提示找不到我的子类(这很正常,因为它是在后面声明的...)
无效请求错误:在初始化映射器 Mapper|Parent|parent 时,表达式 'Child' 无法找到名称(“名称 'Child' 未定义”)。如果这是一个类名,请考虑在定义了两个相关类之后再将这个 relationship() 添加到类中。
但是我该如何定义这个关系,才能避免这个错误呢?
代码如下:
from sqlalchemy import create_engine
from sqlalchemy import Column, Integer, ForeignKey
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker, relationship
from dev.historyMeta import VersionedMeta, VersionedListener
global engine, Base, Session
engine = create_engine('mysql+mysqldb://user:pass@localhost:3306/testdb', pool_recycle=3600)
Base = declarative_base(bind=engine, metaclass=VersionedMeta)
Session = sessionmaker(extension=VersionedListener())
class Parent(Base):
__tablename__ = 'parent'
id = Column(Integer, primary_key=True)
children = relationship("Child", backref="parent")
class Child(Base):
__tablename__ = 'child'
id = Column(Integer, primary_key=True)
parent_id = Column(Integer, ForeignKey('parent.id'))
Base.metadata.create_all()
1 个回答
16
这是我做的方式:
from sqlalchemy import create_engine
from sqlalchemy import Column, Integer, ForeignKey
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker, relationship
engine = create_engine('sqlite://', echo=True)
Base = declarative_base(bind=engine)
Session = sessionmaker(bind=engine)
class Parent(Base):
__tablename__ = 'parent'
id = Column(Integer, primary_key=True)
class Child(Base):
__tablename__ = 'child'
id = Column(Integer, primary_key=True)
parent_id = Column(Integer, ForeignKey('parent.id'))
parent = relationship(Parent, backref='children')
Base.metadata.create_all()