从Python发送文件到Django时出现500错误

0 投票
1 回答
1245 浏览
提问于 2025-04-16 05:27

我找到一个不错的Python模块,可以通过HTTP POST向远程服务器发送数据,叫做 poster。于是我在我的Django应用中写了一个简单的视图,用来接收和存储数据,然后尝试发送一些文件。不幸的是,尽管我按照说明设置了一切,但我还是遇到了 Internal Server Error(内部服务器错误)。有没有人能帮我看看我哪里做错了?

这是我的视图函数:

def upload(request):
    for key, file in request.FILES.items():
        path = '/site_media/remote/'+ file.name
        dest = open(path.encode('utf-8'), 'wb+')
        if file.multiple_chunks:
            for c in file.chunks():
                dest.write(c)
        else:
            dest.write(file.read())
        dest.close()

这是模块的说明:http://atlee.ca/software/poster/,还有一些我参考的说明 http://www.laurentluce.com/?p=20

这是错误追踪信息:

In [15]: print urllib2.urlopen(request).read()
-------> print(urllib2.urlopen(request).read())
---------------------------------------------------------------------------
HTTPError                                 Traceback (most recent call last)

/home/rails/ntt/<ipython console> in <module>()

/bin/python-2.6.2/lib/python2.6/urllib2.pyc in urlopen(url, data, timeout)
    122     if _opener is None:
    123         _opener = build_opener()
--> 124     return _opener.open(url, data, timeout)
    125
    126 def install_opener(opener):

/bin/python-2.6.2/lib/python2.6/urllib2.pyc in open(self, fullurl, data, timeout)
    387         for processor in self.process_response.get(protocol, []):
    388             meth = getattr(processor, meth_name)
--> 389             response = meth(req, response)
    390
    391         return response

/bin/python-2.6.2/lib/python2.6/urllib2.pyc in http_response(self, request, response)
    500         if not (200 <= code < 300):
    501             response = self.parent.error(
--> 502                 'http', request, response, code, msg, hdrs)
    503
    504         return response

/bin/python-2.6.2/lib/python2.6/urllib2.pyc in error(self, proto, *args)
    425         if http_err:
    426             args = (dict, 'default', 'http_error_default') + orig_args
--> 427             return self._call_chain(*args)
    428
    429 # XXX probably also want an abstract factory that knows when it makes


/bin/python-2.6.2/lib/python2.6/urllib2.pyc in _call_chain(self, chain, kind, meth_name, *args)
    359             func = getattr(handler, meth_name)
    360
--> 361             result = func(*args)
    362             if result is not None:
    363                 return result

/bin/python-2.6.2/lib/python2.6/urllib2.pyc in http_error_default(self, req, fp, code, msg, hdrs)
    508 class HTTPDefaultErrorHandler(BaseHandler):
    509     def http_error_default(self, req, fp, code, msg, hdrs):
--> 510         raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
    511
    512 class HTTPRedirectHandler(BaseHandler):

HTTPError: HTTP Error 500: Internal Server Error

当我尝试将文件发送到一个PHP函数时(来自 www.w3schools.com/php/php_file_upload.asp
我用wireshark检查过,我的POST请求发送得没有问题,但之后发生了一些错误,我得到了这个500错误。是不是服务器有什么限制?在上面运行的应用程序上传文件是很顺利的。


把这个视图函数和URL放到不同的服务器上,然后运行:

import httplib
conn = httplib.HTTPConnection("address")
f = open("file, "rb")
conn.request("POST","/upload", f, headers)
response = conn.getresponse()

抛出了:BadStatusLine 异常。

1 个回答

3

这是一个基础的Python问题。在使用某个模块之前,你需要先把它导入。所以只需要在脚本的最上面加上 import urllib 这一行,就可以正常使用了。

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