在Django中使用mod_python运行应用程序时出错

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1 回答
517 浏览
提问于 2025-04-16 04:04

我在使用win32系统,安装了python2.5、django1.2、apache2.2,还有mod_python3.3.1。

我已经正确安装了mod_python。我的应用程序名称是myapp.setting,路径是c:\myapp.setting。在myapp.settings文件夹里,有我的url.py、settings.py等文件。

现在在apache的httpd.conf配置文件中,我做了以下更改:

<Location "/mysite">
    SetHandler python-program
    PythonHandler django.core.handlers.modpython
    SetEnv DJANGO_SETTINGS_MODULE myapp.settings
    PythonDebug On
    PythonPath "['/'] + sys.path"
</Location>

我尝试了很多关于PythonPath的修改。但是当我在浏览器里输入http://localhost/mysite时,出现了以下错误:

MOD_PYTHON错误

ProcessId:      1384
Interpreter:    '192.168.1.166'

ServerName:     '192.168.1.166'
DocumentRoot:   'C:/Program Files/Apache Software Foundation/Apache2.2/htdocs'

URI:            '/mysite'
Location:       '/mysite'
Directory:      None
Filename:       'C:/Program Files/Apache Software Foundation/Apache2.2/htdocs/mysite'
PathInfo:       ''

Phase:          'PythonHandler'
Handler:        'django.core.handlers.modpython'

Traceback (most recent call last):

  File "C:\Python25\Lib\site-packages\mod_python\importer.py", line 1537, in HandlerDispatch
    default=default_handler, arg=req, silent=hlist.silent)

  File "C:\Python25\Lib\site-packages\mod_python\importer.py", line 1229, in _process_target
    result = _execute_target(config, req, object, arg)

  File "C:\Python25\Lib\site-packages\mod_python\importer.py", line 1128, in _execute_target
    result = object(arg)

  File "C:\Python25\Lib\site-packages\django\core\handlers\modpython.py", line 228, in handler
    return ModPythonHandler()(req)

  File "C:\Python25\Lib\site-packages\django\core\handlers\modpython.py", line 191, in __call__
    self.load_middleware()

  File "C:\Python25\Lib\site-packages\django\core\handlers\base.py", line 33, in load_middleware
    for middleware_path in settings.MIDDLEWARE_CLASSES:

  File "C:\Python25\Lib\site-packages\django\utils\functional.py", line 276, in __getattr__
    self._setup()

  File "C:\Python25\Lib\site-packages\django\conf\__init__.py", line 40, in _setup
    self._wrapped = Settings(settings_module)

  File "C:\Python25\Lib\site-packages\django\conf\__init__.py", line 75, in __init__
    raise ImportError("Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e))

ImportError: Could not import settings 'myapp.settings' (Is it on sys.path? Does it have syntax errors?): No module named myapp.settings

请帮帮我,我对Django还很陌生……

1 个回答

2

正如rebus在评论中所说,把你的项目叫做'myapp.settings'是没有意义的。这既不是一个应用程序(应用程序是网站的一个组成部分),也不是一个设置文件。给它起个合适的名字吧——如果你实在想不出来,可以叫它'mysite'。

最后,你应该避免使用mod_python,改用mod_wsgi。

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