等距瓦片图不对齐
我正在制作一个等距的Minecraft克隆游戏,代码运行得很好。我使用了一个四舍五入的函数来调整玩家的位置,这样方块就能对齐到一个网格上。每个方块的图片大小正好是32x32像素,而且图片里的内容都是对称的。
目前,我把四舍五入的函数设置为在X轴上为16像素,在Y轴上为8像素。问题出在Y轴上,因为这样会导致一些方块重叠,如果你不按照正确的顺序放置它们的话。我不知道该怎么解决这个问题,因为我已经尝试过调整四舍五入的函数。希望能得到一些帮助。以下是代码:
import pygame
pygame.init()
win = pygame.display.set_mode((480,320))
pygame.display.set_caption(("Mini Minecraft"))
block = pygame.image.load("Stone.png")
pygame.display.set_icon(block)
background = pygame.image.load("Background.png")
running = True
positions = []
def roundToMultiple(n, m):
return round(n / m) * m
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
pygame.quit()
if event.type == pygame.MOUSEBUTTONDOWN:
placeX, placeY = event.pos
placeXRound = roundToMultiple(placeX, 16)
placeYRound = roundToMultiple(placeY, 8)
positions.append((placeXRound, placeYRound))
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_SPACE:
positions = []
mouseX, mouseY = pygame.mouse.get_pos()
mouseXRound = roundToMultiple(mouseX, 16)
mouseYRound = roundToMultiple(mouseY, 8)
if mouseXRound > 448:
mouseXRound = 448
if mouseYRound > 288:
mouseYRound = 288
win.blit(background, (0,0))
for pos in positions:
win.blit(block, pos)
win.blit(block, (mouseXRound, mouseYRound))
pygame.display.update()
1 个回答
1
你只需要把点的列表排序。根据x坐标进行排序,同时把y坐标反向排序(也就是说,y坐标越大的排在前面,越小的排在后面)。可以用这段代码来实现:positions.sort(key=lambda p: (p[0], -p[1]))
:
if event.type == pygame.MOUSEBUTTONDOWN:
placeX, placeY = event.pos
placeXRound = roundToMultiple(placeX, 16)
placeYRound = roundToMultiple(placeY, 8)
positions.append((placeXRound, placeYRound))
positions.sort(key=lambda p: (p[0], -p[1]))