在模板中为Django分页器过滤结果

Question

我正在使用一个通用视图来过滤我的页面对象，只显示与当前由django-cms设置的语言相同的条目（http://www.django-cms.org/en/documentation/2.0/i18n/）。

这个方法运行得很好，但当我加入Django的分页功能时（http://docs.djangoproject.com/en/1.2/topics/pagination/），过滤后的结果仍然被计算在内。举个例子，如果有三条英文结果，而总共有十条结果，分页设置为2，那么我会得到5个结果页面，其中大部分当然是空白的，因为剩下的七条结果的过滤是在模板中进行的。

我可以修改Django的分页器，让它和模板中的过滤一起工作吗？还是说我必须重建我的视图？如果是这样，我该怎么做呢？

相关代码：

managers.py

def update_queryset(view, queryset, queryset_parameter='queryset'):
    '''Decorator around views based on a queryset passed in parameter, which will force the update of the queryset before executing the view.
    Related to issue: http://code.djangoproject.com/ticket/8378'''
    def wrap(*args, **kwargs):
        #Regenerate the queryset before passing it to the view.
        kwargs[queryset_parameter] = queryset()
        return view(*args, **kwargs)
    return wrap

views/entries.py

from django.views.generic.list_detail import object_list
from cmsplugin_publisher.models import Entry
from cmsplugin_publisher.managers import update_queryset

entry_index = update_queryset(object_list, Entry.published.all)

urls/entries.py

from django.conf.urls.defaults import *
from cmsplugin_publisher.models import Entry
from cmsplugin_publisher.settings import PAGINATION, ALLOW_EMPTY, ALLOW_FUTURE

entry_conf_list = {'queryset': Entry.published.all(), 'paginate_by': PAGINATION}

entry_conf = { 'queryset': Entry.published.all(),}

entry_conf_detail = entry_conf.copy()
entry_conf_detail['queryset'] = Entry.objects.all()

urlpatterns = patterns('cmsplugin_publisher.views.entries',
    url(r'^$', 'entry_index', entry_conf_list, name='cmsplugin_publisher_entry_archive_index'),
    url(r'^(?P<page>[0-9]+)/$', 'entry_index', entry_conf_list, name='cmsplugin_publisher_entry_archive_index_paginated'),
)

urlpatterns += patterns('django.views.generic.list_detail',
    url(r'^(?P<slug>[-\w]+)/$', 'object_detail', entry_conf_detail, name='cmsplugin_publisher_entry_detail'),
)

在 entry_list.html 中

{% block content %}
    {% for object in object_list %}
      {% ifequal object.language current_language %}
        ..
      {% endifequal %}
    {% endfor %}
    {% if is_paginated %}
    <ul id="pagination">
    {% if page_obj.has_previous %}
        {% ifnotequal page_obj.start_index 1 %}<li><a href="../" title="{% trans 'View Latest Entries' %}">{% trans 'Latest Entries' %}</a></li>{% endifnotequal %}
        {% ifequal page_obj.previous_page_number 1 %}{% endifequal %}
        {% ifnotequal page_obj.previous_page_number 1 %}
            <li><a href="../{{ page_obj.previous_page_number }}/" title="{% trans 'View Earlier Entries' %}">{% trans 'Earlier Entries' %}</a></li>
        {% endifnotequal %}
    {% else%}
    {% endif %}
    <li>{% trans 'Page' %} {{ page_obj.start_index }} {% trans 'of' %} {{ paginator.num_pages }} {% trans 'Entries' %}</li>
    {% if page_obj.has_next %}
        {% ifnotequal page_obj.start_index 1 %}
            <li><a href="../{{ page_obj.next_page_number }}/" title="{% trans 'View Older Entries' %}">{% trans 'Older Entries' %}</a></li>
        {% endifnotequal %}
        {% ifequal page_obj.start_index 1 %}
        <li><a href="{{ page_obj.next_page_number }}/" title="{% trans 'View Older Entries' %}">{% trans 'Older Entries' %}</a></li>
        {% endifequal %}
    {% else%}
    {% endif %}
    </ul>
{% endif %}

如果你们能给出一些好的解决方案，我会非常感激。

django queryset pagination django-cms template filtering language localization generic views empty pages

在模板中为Django分页器过滤结果

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