使用BeautifulSoup从下拉列表加载的名称和值查找集合
在我的HTML页面上,我有一个下拉列表:
<select name="somelist">
<option value="234234234239393">Some Text</option>
</select>
为了得到这个列表,我正在做:
ddl = soup.findAll('select', name="somelist")
if(ddl):
???
现在我需要帮助来处理这个集合/字典,我想通过‘一些文本’和234234234239393这两个方式来查找。
这可能吗?
3 个回答
0
再来一次,给大家展示一下怎么用pyparsing来做到这一点:
html = r'''
<select name="somelist">
<option value="234234234239393">Some Text</option>
<option value="42">Other text</option>
</select>
'''
from pyparsing import makeHTMLTags, Group, SkipTo, withAttribute, OneOrMore
select,selectEnd = makeHTMLTags("SELECT")
option,optionEnd = makeHTMLTags("OPTION")
optionEntry = Group(option("option") +
SkipTo(optionEnd)("menutext") +
optionEnd)
somelistSelect = (select.setParseAction(withAttribute(name="somelist")) +
OneOrMore(optionEntry)("options") +
selectEnd)
t,_,_ = somelistSelect.scanString(html).next()
for op in t.options:
print op.menutext, '->', op.option.value
输出结果是:
Some Text -> 234234234239393
Other text -> 42
1
这里有一种方法..
ddl_list = soup.findAll('select', attrs={'name': 'somelist'})
if ddl_list:
ddl = ddl_list[0]
# find the optino by value=234234234239393
opt = ddl.findChild('option', attrs={'value': '234234234239393'})
if opt:
# do something
# this list will hold all "option" elements matching 'Some Text'
opt_list = [opt for opt in ddl.findChildren('option') if opt.string == u'Some Text']
if opt_list:
opt2 = opt_list[0]
# do something
5
可以试试下面的代码来开始:
str = r'''
<select name="somelist">
<option value="234234234239393">Some Text</option>
<option value="42">Other text</option>
</select>
'''
soup = BeautifulSoup(str)
select_node = soup.findAll('select', attrs={'name': 'somelist'})
if select_node:
for option in select_node[0].findAll('option'):
print option
这段代码会打印出所有的 option
节点:
<option value="234234234239393">Some Text</option>
<option value="42">Other text</option>
现在,对于每一个 option
,option['value']
是它的值属性,而 option.text
是标签里面的文本内容(比如“某些文本”)