如何将列表作为参数传递给Python C模块？

Question

我找到了一篇很不错的文章，里面讲了一个Python C模块的例子。在这个例子中，只有一个整数被作为参数传递。那我想问，怎么才能把一个Python列表作为参数传递呢？

Answer 1

使用其中一个 O 参数 和 序列协议。

Answer 2

来自 http://code.activestate.com/lists/python-list/31841/:

...
char * tok;         /* delimiter tokens for strtok */
int cols;           /* number of cols to parse, from the left */

int numLines;       /* how many lines we passed for parsing */
char * line;        /* pointer to the line as a string */
char * token;       /* token parsed by strtok */

PyObject * listObj; /* the list of strings */
PyObject * strObj;  /* one string in the list */

/* the O! parses for a Python object (listObj) checked
   to be of type PyList_Type */
if (! PyArg_ParseTuple( args, "O!is", &PyList_Type, &listObj, 
           &cols, &tok )) return NULL;

/* get the number of lines passed to us */
numLines = PyList_Size(listObj);

/* should raise an error here. */
if (numLines < 0)   return NULL; /* Not a list */

...

/* iterate over items of the list, grabbing strings, and parsing
   for numbers */
for (i=0; i<numLines; i++){

/* grab the string object from the next element of the list */
strObj = PyList_GetItem(listObj, i); /* Can't fail */

/* make it a string */
line = PyString_AsString( strObj );

/* now do the parsing */

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