如何使用ManyToMany字段填充默认表单数据?

6 投票
1 回答
1871 浏览
提问于 2025-04-15 23:37

好吧,我在谷歌和Django的文档上搜索了超过两个小时(还有在freenode的IRC频道),但就是搞不明白这个问题。

基本上,我有一个叫做 Room 的模型,下面是它的定义:

class Room(models.Model):
    """
    A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each
    room has a variable amount of `Caller`s, and usually a moderator of some
    sort. Each `Partyline` has many rooms, and it is common for `Caller`s to
    join multiple rooms over the duration of their call.
    """
    LIVE = 0
    PRIVATE = 1
    ONE_ON_ONE = 2
    UNCENSORED = 3
    BULLETIN_BOARD = 4
    CHILL = 5
    PHONE_BOOTH = 6
    TYPE_CHOICES = (
        ('LR', 'Live Room'),
        ('PR', 'Private Room'),
        ('UR', 'Uncensored Room'),
    )

    type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES)
    number = models.IntegerField('Room Number')
    partyline = models.ForeignKey(Partyline)
    owner = models.ForeignKey(User, blank=True, null=True)
    bans = models.ManyToManyField(Caller, blank=True, null=True)

    def __unicode__(self):
        return "%s - %s %d" % (self.partyline.name, self.type, self.number)

我还有一个 forms.py 文件,里面有一个 ModelForm,用来表示我的 Room 模型:

from django.forms import ModelForm

from partyline_portal.rooms.models import Room


class RoomForm(ModelForm):
    class Meta:
        model = Room

我正在创建一个视图,让管理员可以编辑特定的 Room 对象。到目前为止,我的视图是这样的:

def edit_room(request, id=None):
    """
    Edit various attributes of a specific `Room`. Room owners do not have
    access to this page. They cannot edit the attributes of the `Room`(s) that
    they control.
    """
    room = get_object_or_404(Room, id=id)
    if not room.is_owner(request.user):
        return HttpResponseForbidden('Forbidden.')

    if is_user_type(request.user, ['admin']):
        form_type = RoomForm
    elif is_user_type(request.user, ['lm']):
        form_type = LineManagerEditRoomForm
    elif is_user_type(request.user, ['lo']):
        form_type = LineOwnerEditRoomForm

    if request.method == 'POST':
        form = form_type(request.POST, instance=room)
        if form.is_valid():
            if 'owner' in form.cleaned_data:
                room.owner = form.cleaned_data['owner']

        room.save()
    else:
        defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id}
        if room.owner:
            defaults['owner'] = room.owner.id
        if room.bans:
            defaults['bans'] = room.bans.all() ### this does not work properly!

        form = form_type(defaults, instance=room)

    variables = RequestContext(request, {'form': form, 'room': room})
    return render_to_response('portal/rooms/edit.html', variables)

现在,这个视图在我查看页面时工作得很好。它显示了所有表单属性,所有默认值都填好了(当用户进行GET请求时)……除了 ManyToMany 字段 'bans' 的默认值。

简单来说,如果管理员点击一个 Room 对象进行编辑,他们会看到所有 Room 的默认值,除了 'bans'。无论我怎么做,我都找不到办法让Django显示当前被“禁用的用户”对于这个 Room 对象。这里是需要修改的代码行(来自视图):

defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id}
if room.owner:
        defaults['owner'] = room.owner.id
if room.bans:
        defaults['bans'] = room.bans.all() ### this does not work properly!

我肯定还有其他语法需要用来指定 'bans' 字段的默认值。我真的为这个问题抓狂,非常希望能得到一些帮助。

谢谢!

更新

lazerscience 实际上在他的评论中帮我找到了解决方案。基本上,它的工作原理是如果你传递一个主键的列表。为了让它工作,我必须把:

if room.bans:
        defaults['bans'] = room.bans.all() ### this does not work properly!

改成

if room.bans:
        defaults['bans'] = [b.pk for b in room.bans.all()]

然后就好了,立刻开始工作了(当我查看页面时,它会显示一个可选择的 Caller 列表,已经被禁用的呼叫者会被高亮显示(选中状态)。

1 个回答

0

你可能需要使用“initial”这个选项:Django 设置表单默认值

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