如何获取GtkTreeModel最后一行的GtkTreePath或GtkTreeIter?
我想获取一个GtkTreePath或GtkTreeIter,指向GtkTreeModel中的最后一行,但GtkTreeModel没有提供这样的功能。
我很高兴看到用C语言、Python语言,或者两者都有的回答和例子;)。
4 个回答
2
这是我目前的做法,但感觉有点笨拙...
C语言的例子:
void get_iter_last( GtkTreeModel *mdl, GtkTreeIter *itr )
{
GtkTreeIter i;
if ( gtk_tree_model_get_iter_first( mdl, &i ) ) {
while ( gtk_tree_model_iter_next( mdl, &i ) ) {
*itr = i;
}
}
}
Python语言的例子:
def get_iter_last( mdl ):
itr = mdl.get_iter_first()
last = None
while itr:
last = itr
itr = mdl.iter_next( itr )
return last
3
虽然unwind的回答是正确的,并且足以让我走上正轨,但我觉得为了完整起见,我还是想分享一下我的最终解决方案:
Python:
def model_get_iter_last( model, parent=None ):
"""Returns a gtk.TreeIter to the last row or None if there aren't any rows.
If parent is None, returns a gtk.TreeIter to the last root row."""
n = model.iter_n_children( parent )
return n and model.iter_nth_child( parent, n - 1 )
C:
/**
* Set itr_last to last item of parent if parent has any rows.
* If parent is NULL, set itr_last to last root row.
* Returns TRUE if itr_last could be set, otherwise FALSE.
*/
gboolean model_get_iter_last( GtkTreeModel *model,
GtkTreeIter *itr_last,
GtkTreeIter *parent )
{
gboolean success;
gint n;
if ( n = gtk_tree_model_iter_n_children( model, parent ) ) {
success = gtk_tree_model_iter_nth_child( model, itr_last, parent, n - 1 );
}
else {
itr_last = NULL;
success = FALSE;
}
return success;
}
4
你可以尝试使用GtkTreePath,这可能有点像小技巧,但还是在这个API的范围内:
GtkTreePath *path;
GtkTreeIter iter;
/* With NULL as iter, we get the number of toplevel nodes. */
gint rows = gtk_tree_model_iter_n_children(GTK_TREE_MODEL(model), NULL);
/* Now get a path from the index. */
path = gtk_tree_path_new_from_indices(rows - 1, -1);
/* Ask the model for an iter to the node identified by the path. */
gtk_tree_model_get_iter(GTK_TREE_MODEL(model), &iter, path);
/* Drop the path, we're done with it, iter is final output. */
gtk_tree_path_free(path);
注意:我没有实际测试上面的代码,不过我很确定我在真实代码中做过类似的事情。