提取嵌入视频源链接 Python Selenium

Question

这个网站有五个服务器流可以看所有电影，它告诉你怎么轻松获取第二个服务器的链接。谢谢大家的帮助。

def extract_embed_video(self):
        self.clear()
        self.logo()
        print(Fore.CYAN + 'There are 5 servers to choose from' + Style.RESET_ALL)
        selected = input(Fore.LIGHTGREEN_EX + 'choose between 1-5 > ' + Style.RESET_ALL)
        if selected == '1':
            self.extract_server1()
        elif selected == '2':
            self.extract_server2() # //*[@id="oframeplayer"]/pjsdiv[1]/video/source
        elif selected == '3':
            self.extract_server3() 
        elif selected == '4':
            self.extract_server4()
        elif selected == '5':
            self.extract_server5()

这是代码，正如你所看到的，我找到了第二个服务器流的xpath。