在Python中通过multiprocessing.Pipe()进行异步发送和接收

3 投票
1 回答
5203 浏览
提问于 2025-04-15 22:41

我在这段代码中遇到了一些问题,想让Pipe.send这个功能正常工作。我最终想要实现的是在一个子进程运行时,能够发送和接收消息到这个子进程和从它那里接收消息。这个功能最终会被整合进一个pexpect循环,用来和解释器进程进行交流。

from multiprocessing import Process, Pipe
from pexpect import spawn


class CockProc(Process):

    def start(self):
        self.process = spawn('coqtop', ['-emacs-U'])

    def run(self, conn):
        while True:
            if not conn.poll():
                cmd = conn.recv()
                self.process.send(cmd)
            self.process.expect('\<\/prompt\>')
            result = self.process.before + self.process.after + " "
            conn.send(result)


q, p = Pipe()

proc = CockProc()
proc.start()
proc.run(p)
res = q.recv()
command = raw_input(res + " ")

q.send(command)
res = q.recv()
parent_conn.send('OHHAI')
p.join()
    `

1 个回答

1

这个可以用,但可能还需要进一步调整。我不太确定我能创建多少个这样的东西,然后再循环处理它们。

from multiprocessing import Process, Pipe
from pexpect import spawn


class CockProc(Process):

    def start(self):
        self.process = spawn('coqtop', ['-emacs-U'])

    def run(self, conn):
        if conn.poll():
            cmd = conn.recv()
            self.process.send(cmd + "\n")
            print "sent comm"
        self.process.expect('\<\/prompt\>')
        result = self.process.before + self.process.after + " "
        conn.send(result)

here, there = Pipe(duplex=True)

proc = CockProc()
proc.start()
proc.run(there)

while True:
    if here.poll():
        res = here.recv()
        command = raw_input(res + " ")
        here.send(command)
    proc.run(there)

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