在Django表单中验证ModelChoiceField
我正在尝试验证一个包含 ModelChoiceField 的表单:
forms.py:
from django import forms
from modelchoicetest.models import SomeObject
class SomeObjectAddForm(forms.ModelForm):
class Meta:
model = SomeObject
models.py:
from django.db import models
class SomeChoice(models.Model):
name = models.CharField(max_length=16)
def __unicode__(self):
return self.name
class SomeObject(models.Model):
choice = models.ForeignKey(SomeChoice)
views.py:
from django.shortcuts import render_to_response
from django.template import RequestContext
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse
from forms import SomeObjectAddForm
def add(request):
if request.method == 'POST':
form = SomeObjectAddForm(request.POST)
if form.is_valid():
form.save()
return HttpResponseRedirect(reverse('modelchoicetest_add'))
else:
form = SomeObjectAddForm()
return render_to_response('modelchoicetest/index.html',
{'form': form},
context_instance=RequestContext(request))
在正常情况下使用时,一切都很顺利。但我想要保护这个表单,避免无效输入。很明显,当我在这个字段中输入无效值时,我应该得到 forms.ValidationError,对吧?但是如果我尝试提交一个在 'somechoice' 字段中填入 'invalid' 的表单,我得到的是:
ValueError: invalid literal for int() with base 10: 'invalid'
而不是预期中的 forms.ValidationError。我该怎么办呢?我尝试在这里放一个 def clean_somechoice(self)
来检查这个字段,但那并没有奏效:ValueError 在它到达 clean_somechoice()
之前就发生了。
而且我觉得这不是一个好的解决方案,应该有更简单的方法,但我就是没想到。
这是完整的错误追踪信息:
Traceback:
File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py" in get_response
101. response = callback(request, *callback_args, **callback_kwargs)
File "/home/andrey/public_html/example/modelchoicetest/views.py" in add
11. if form.is_valid():
File "/usr/local/lib/python2.6/dist-packages/django/forms/forms.py" in is_valid
120. return self.is_bound and not bool(self.errors)
File "/usr/local/lib/python2.6/dist-packages/django/forms/forms.py" in _get_errors
111. self.full_clean()
File "/usr/local/lib/python2.6/dist-packages/django/forms/forms.py" in full_clean
276. value = field.clean(value)
File "/usr/local/lib/python2.6/dist-packages/django/forms/fields.py" in clean
154. value = self.to_python(value)
File "/usr/local/lib/python2.6/dist-packages/django/forms/models.py" in to_python
911. value = self.queryset.get(**{key: value})
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py" in get
330. clone = self.filter(*args, **kwargs)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py" in filter
536. return self._filter_or_exclude(False, *args, **kwargs)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py" in _filter_or_exclude
554. clone.query.add_q(Q(*args, **kwargs))
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py" in add_q
1109. can_reuse=used_aliases)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py" in add_filter
1048. connector)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/where.py" in add
66. value = obj.prepare(lookup_type, value)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/where.py" in prepare
267. return self.field.get_prep_lookup(lookup_type, value)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/fields/__init__.py" in get_prep_lookup
314. return self.get_prep_value(value)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/fields/__init__.py" in get_prep_value
496. return int(value)
Exception Type: ValueError at /
Exception Value: invalid literal for int() with base 10: 'invalid'
2 个回答
0
1
看起来这个错误是由实际的 ModelChoiceField
对象的 clean
方法引发的。因为这是一个外键,Django 期待的是一个 int
类型的值,这个值代表了 SomeChoice
的主键(pk
)。你到底是怎么把 invalid
传递给表单的呢?
对评论的回应
如果你真的觉得需要处理这个问题,可以尝试重写默认的 ModelChoiceField
,创建一个新的字段叫 choice
,并在 ModelChoiceField
的 __init__
方法中传入 to_field_name
这个参数。这样 Django 就不会根据主键进行过滤,也就不会引发那个错误了。
不过我个人不建议使用这个方法。没有必要去迎合那些试图破解你表单的用户。