tkinter GUI编程中的AttributeError

Question

我想在Python的图形界面窗口中显示我计算的结果。我正在尝试使用Tkinter，但在Tkinter的控件上显示输出时遇到了问题。我把地址信息输入到Tkinter窗口的文本框中，想把这个地址的纬度和经度显示在文本标签上。有没有人能帮我解决这个问题？我对Tkinter还比较陌生。

下面是我的代码：

def initialize(self):
    self.grid()

    self.entry = Tkinter.Entry(self)
    self.entry.grid(column=0,row=0,sticky='EW')

    button = Tkinter.Button(self,text=u"Get Geo information !",command=self.OnButtonClick)
    button.grid(column=1,row=0)

    self.labelVariable = Tkinter.StringVar()

    label = Tkinter.Label(self,textvariable=self.labelVariable,
                          anchor="w",fg="black",bg="white")
    label.grid(column=0,row=1,columnspan=2,sticky='EW')

    self.grid_columnconfigure(0,weight=1)
    self.resizable(True,False)


def OnButtonClick(self):
    outf = open(out_file,'w')
    outf_failed = open(out_file_failed,'w')
    #inf = open(addr_file,'r')
    inf = codecs.open(addr_file, 'r', 'iso-8859-1')

    for address in inf:
        #get latitude and longitude of address
        data = geocode(address)

        #output results and log to file

         if len(data)>1:

             self.labelVariable.set( self.entryVariable.get()+" (Latitude )", data['lat'] )
             self.labelVariable.set( self.entryVariable.get()+" (Longitude )", data['lng'] )

             outf.write(address.strip()+data['lat']+','+data['lng']+'\n')
                    outf.flush()
         else:
             self.labelVariable.set( self.entryVariable.get()+" Geocoding of '"+addr_file+"' failed with error code "+data['code'] )

             outf_failed.write(address)

             outf_failed.flush()

         time.sleep(sleep_time)

    #clean up
    inf.close()
    outf.close()
    outf_failed.close()


if __name__ == "__main__":
    app = simpleapp_tk(None)
    app.title('Your Location')
    app.mainloop()

然后我遇到了错误：

File "F:\JavaWorkspace\Test\src\gui_geo_location.py", line 94, in OnButtonClick
    self.labelVariable.set( self.entryVariable.get()+" (Latitude )", data['lat'] )
  File "C:\Python25\lib\lib-tk\Tkinter.py", line 1721, in __getattr__
    return getattr(self.tk, attr)
AttributeError: entryVariable

这是我的 __init__ 方法：

def __init__(self,parent):
        Tkinter.Tk.__init__(self,parent)
        self.parent = parent
        self.initialize()

def initialize(self):
        self.grid()

        self.entry = Tkinter.Entry(self)
        self.entry.grid(column=0,row=0,sticky='EW')
        self.entry.bind("<Return>", self.OnPressEnter)

        button = Tkinter.Button(self,text=u"Get Geo information !",command=self.OnButtonClick)
        button.grid(column=1,row=0)

        self.labelVariable = Tkinter.StringVar()

        label = Tkinter.Label(self,textvariable=self.labelVariable,
                              anchor="w",fg="black",bg="white")
        label.grid(column=0,row=1,columnspan=2,sticky='EW')

        self.grid_columnconfigure(0,weight=1)
        self.resizable(True,False)

tkinter 事件处理数据显示 GUI编程界面设计 attributeerror

tkinter GUI编程中的AttributeError

1 个回答

撰写回答