如何在SQLAlchemy中执行INSERT INTO t1 (SELECT * FROM t2)?
在SQLAlchemy中,我该如何从一个SELECT
语句填充或更新一个表呢?
3 个回答
1
正如Noslko在评论中提到的,现在你可以不再使用原始的SQL语句了:
from sqlalchemy.ext.compiler import compiles
from sqlalchemy.sql.expression import Executable, ClauseElement
class InsertFromSelect(Executable, ClauseElement):
def __init__(self, table, select):
self.table = table
self.select = select
@compiles(InsertFromSelect)
def visit_insert_from_select(element, compiler, **kw):
return "INSERT INTO %s (%s)" % (
compiler.process(element.table, asfrom=True),
compiler.process(element.select)
)
insert = InsertFromSelect(t1, select([t1]).where(t1.c.x>5))
print insert
生成的结果是:
INSERT INTO mytable (SELECT mytable.x, mytable.y, mytable.z FROM mytable WHERE mytable.x > :x_1)
34
从0.8.3版本开始,你可以直接在sqlalchemy中使用这个功能:Insert.from_select:
sel = select([table1.c.a, table1.c.b]).where(table1.c.c > 5)
ins = table2.insert().from_select(['a', 'b'], sel)
79
SQLalchemy不会自动为你构建这个结构。你可以使用文本查询。
session.execute('INSERT INTO t1 (SELECT * FROM t2)')
编辑:
一年多以后,现在在sqlalchemy 0.6+版本中,你可以创建它:
from sqlalchemy.ext import compiler
from sqlalchemy.sql.expression import Executable, ClauseElement
class InsertFromSelect(Executable, ClauseElement):
def __init__(self, table, select):
self.table = table
self.select = select
@compiler.compiles(InsertFromSelect)
def visit_insert_from_select(element, compiler, **kw):
return "INSERT INTO %s (%s)" % (
compiler.process(element.table, asfrom=True),
compiler.process(element.select)
)
insert = InsertFromSelect(t1, select([t1]).where(t1.c.x>5))
print insert
生成的结果是:
"INSERT INTO mytable (SELECT mytable.x, mytable.y, mytable.z FROM mytable WHERE mytable.x > :x_1)"
另一个编辑:
现在,四年后,这个语法已经被整合进SQLAlchemy 0.9,并且也回溯到0.8.3版本;你可以创建任何select()
,然后使用Insert
对象的新from_select()
方法:
>>> from sqlalchemy.sql import table, column
>>> t1 = table('t1', column('a'), column('b'))
>>> t2 = table('t2', column('x'), column('y'))
>>> print(t1.insert().from_select(['a', 'b'], t2.select().where(t2.c.y == 5)))
INSERT INTO t1 (a, b) SELECT t2.x, t2.y
FROM t2
WHERE t2.y = :y_1