Django TypeError get_object_or_404() 至少需要 1 个参数(给定 0 个)

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2 回答
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提问于 2025-04-28 16:23

我正在做一个博客,并且在学习django的过程中遇到了一些问题。我想把网址设置成既包含文章的别名(slug)又包含文章的ID。

当我在管理面板点击“在网站上查看”链接时,出现了这个错误: NoReverseMatch at /admin/r/7/2/ 找不到名为'article'的反向链接,参数是'(u'test-post-3', '2')',没有找到对应的模式。尝试了0个模式。

当我手动输入网址时,出现了这个错误: TypeError at /articles/test-post-3,2/ get_object_or_404() 至少需要1个参数(给了0个) 这是我的代码:

views.py:

from django.shortcuts import render, get_object_or_404
from django.http import HttpResponse, HttpResponseRedirect
from django.template import RequestContext, loader
from django.core.urlresolvers import reverse
from django.views import generic
from django.utils import timezone

# Create your views here.

from articles.models import Content

class IndexView(generic.ListView):
    template_name = 'articles/index.html'
    context_object_name = 'latest_articles_list'

    def get_queryset(self):
        return Content.objects.filter(
            published_date__lte=timezone.now()
        ).order_by('-published_date')[:5]

def detail(request, slugline, id):
    article = get_object_or_404(pk=id)
    return render(request, 'articles/detail.html', {'article': article})

urls.py:

from django.conf.urls import patterns, url
from articles import views

urlpatterns = patterns('',
    url(r'^$', views.IndexView.as_view(), name = 'index'),
    #url(r'^(?P<slugline>[-\w\d]+), (?P<pk>\d+)/$', views.DetailView.as_view(), name='detail')
    url(r'^(?P<slugline>[-\w\d]+),(?P<id>\d+)/$', view=views.detail, name='article'),
)

models.py:

from django.db import models
from django.db.models import permalink
from django.utils import timezone
import datetime
# Create your models here.


class Content(models.Model):
    title = models.CharField(max_length=100, unique=True)
    slugline = models.SlugField(max_length=100, unique=True)
    body = models.TextField()
    published_date = models.DateTimeField('date published')

    def __unicode__(self):
        return self.title

    @permalink
    def get_absolute_url(self):
        # return ('article', (), {
            # 'slugline': self.slugline,
            # 'id': self.id,
        # })
        from django.core.urlresolvers import reverse
        return reverse('article', args=[self.slugline, str(self.id)])

    def was_published_recently(self):
        now = timezone.now()
        return now - datetime.timedelta(days=1) <= self.published_date <= now
    was_published_recently.admin_order_field = 'published_date'
    was_published_recently.boolean = True
    was_published_recently.short_description = 'Published recently?'

主urls.py:

from django.conf.urls import patterns, include, url

from django.contrib import admin
admin.autodiscover()

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'the_Bluntist.views.home', name='home'),
    # url(r'^blog/', include('blog.urls')),

    url(r'^articles/', include('articles.urls', namespace="articles")),
    url(r'^admin/', include(admin.site.urls)),
)
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2 个回答

0
article = get_object_or_404(pk=id)

你必须同时传入模型和过滤器才能进行调用。这里有相关文档

article = get_object_or_404(klass, pk=id)
2

你对 get_object_or_404 的使用不太正确:

文档说明:

get_object_or_404(klass, *args, **kwargs)

这个函数会用 get() 来返回一个对象,如果找不到这个对象,就会抛出一个 Http404 异常,表示页面不存在。

klass 可以是一个 Model(模型)、Manager(管理器)或者 QuerySet(查询集)对象。其他传入的参数和关键字参数会用于 get() 查询。

注意:如果找到多个对象,就会抛出 MultipleObjectsReturned 异常。

你可以这样使用:

  • article = get_object_or_404(Article, pk=id)
  • article = get_object_or_404(Article.objects, pk=id)
  • article = get_object_or_404(Article.objects.all(), pk=id)
  • article = get_object_or_404(Article.objects.filter(pk=id)

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