如何在Django中创建特定的if条件模板标签?
我的问题是关于一个if条件的。
我想要实现类似的功能,但不知道该怎么做。
{% if restaurant.is_favorite_of(user) %}
<img src="{{MEDIA_URL}}images/favorite_on.png" alt="This restaurant is one of your favorite (Click to undo)" />
{% else %}
<img src="{{MEDIA_URL}}images/favorite_off.png" alt="This restaurant is not one of your favorite (Click to add to your favorite)" />
{% endif %}
在我的收藏管理器中,我创建了:
def is_favorite(self, user, content_object):
"""
This method returns :
- True if content_object is favorite of user
- False if not
>>> user = User.objects.get(username="alice")
>>> fav_user = User.objects.get(username="bob")
>>> fav1 = Favorite.create_favorite(user, fav_user)
>>> Favorite.objects.is_favorite(user, fav_user)
True
>>> Favorite.objects.is_favorite(user, user)
False
>>> Favorite.objects.all().delete()
Above if we test if bob is favorite of alice it is true.
But alice is not favorite of alice.
"""
ct = ContentType.objects.get_for_model(type(content_object))
try:
self.filter(user=user).filter(content_type = ct).get(object_id = content_object.id)
return True
except Favorite.DoesNotExist:
return False
因为在Django模板中没有办法这样做,所以我可以做一个模板标签来实现这个功能:
{% is_favorite user resto %}
<img src="{{MEDIA_URL}}images/favorite_on.png" alt="This restaurant is one of your favorite (Click to undo)" />
{% else %}
<img src="{{MEDIA_URL}}images/favorite_off.png" alt="This restaurant is not one of your favorite (Click to add to your favorite)" />
{% endif %}
但是该怎么做呢?你们有没有更好的主意?
3 个回答
0
当其他方法都不奏效时,你可以使用{% expr whatever %}这个标签来计算一个值,并把它放进一个变量里,这样你就可以在你的模板中使用它。我通常不让设计师知道这个方法,但有时候这是唯一有效的办法,除了倒立之外……你懂的。
2
也许我可以使用包含标签。
创建一个这样的标签:
{% show_favorite_img user restaurant %}
templatetags/user_extra.py :
@register.inclusion_tag('users/favorites.html')
def show_favorite_img(user, restaurant):
return {'is_favorite': Favorite.objects.is_favorite(user, restaurant)}
11
最简单的方法就是创建一个过滤器。
@register.filter
def is_favourite_of(object, user):
return Favourite.objects.is_favourite(user, object)
然后在模板里使用它:
{% if restaurant|is_favourite_of:user %}