Django 依赖下拉选择

11 投票
4 回答
23632 浏览
提问于 2025-04-20 05:55

我知道这个问题有很多答案,但我刚开始学习Django,不知道怎么实现这些解决方案。首先,我想做的事情是这样的。这是我的模型:

class Region(models.Model):

    name = models.CharField(max_length=255, verbose_name=_("Name"))
    slug = models.SlugField(max_length=150, unique=True, null=True)

    def save(self,*args, **kwargs):
        if not self.slug:
            self.slug = slugify(self.name)
        super(Region,self).save(*args,**kwargs)

    def __unicode__(self):
        return u'%s' % (self.name)

    class Meta:
        verbose_name = _('Region')
        verbose_name_plural = _('Regions')

class District(models.Model):

    name = models.CharField(max_length=255, verbose_name=_("Name"))
    slug = models.SlugField(max_length=150, unique=True, null=True)
    region = models.ForeignKey(Region,verbose_name=_("Region"))

    def save(self, *args, **kwargs):
        if not self.slug:
            self.slug = slugify(self.name)
        super(District, self).save(*args, **kwargs)

    def is_in_region(self, region):
        if self.region == region:
            return True
        else:
            return False

    def __unicode__(self):
        return u'%s' % (self.name)

    class Meta:
        verbose_name = _("District")
        verbose_name_plural = _("Districts")

在前端页面,我想选择一个地区,然后根据选择的地区显示该地区的区。这是我的视图:

class SearchView(ListView):

    template_name = 'advert/list_view.html'

    def all_json_models(self, request, region):
        current_reg = Region.objects.get(slug=region)
        districts = District.objects.all().filter(region=current_reg)
        json_models = serializers.serialize("json", districts)
        return http.HttpResponse(json_models, mimetype="application/javascript")

    def get(self, request, *args, **kwargs): 
        return self.post(request, *args, **kwargs)

    def post(self, request, *args, **kwargs):
        self.request = request
        try:
            self.page = int(self.request.GET.get('page','1'))
        except:
            self.page = 1
        self.queryset = ""
        return super(SearchView, self).get(request, *args, **kwargs)

    def get_queryset(self):
        """We have to bypass the queryset because
        we are joining several object lists together. """
        return None

    def get_context_data(self, **kwargs):
        context['regions'] = Region.objects.all().order_by("name")
        return context

get_context_data这个方法其实很长,但我这里只写了一个简单的版本。我参考了这个网站的解决方案 http://www.devinterface.com/blog/en/2011/02/how-to-implement-two-dropdowns-dependent-on-each-other-using-django-and-jquery/ 。但是,选择区的功能还是没有正常工作。我尝试在视图类中写一个叫做all_json_models的方法,但这个方法还是没有被调用。有没有人能告诉我这是为什么吗?非常感谢!

4 个回答

0

这里有一个更新的关于AJAX代码的回答,还有一些补充说明。你只需要把#selectyear改成你选择框的ID,然后把变量schedule_year改成一个更符合你数据的名字。接着在成功的回调中,把#selectschedule改成你的第二个选择框的ID。注意,result[i].schedule_name是从视图中返回的值的名字。查看views.py中的result_set,根据你的数据相应地修改名字。

如果你想实现超过两个联动选择框,其实很简单。只需复制下面的代码,把每个选择框的代码串联起来,直到满足你的需求。可以重复使用同一个视图,配合条件语句,或者再添加一个视图来返回新的结果。

javascript和AJAX

<script>
$(document).ready(function(){
    //handle selected year
    $('select#selectyear').change(function () {
        var optionSelected = $(this).find("option:selected");
        var valueSelected  = optionSelected.val();
        var schedule_year   = optionSelected.text();
        $.ajax({
            url: 'getdetails/',
            type: 'GET',
            data: {'year' : JSON.stringify(schedule_year)},
            success:    function(result){
                            //remove previous selections
                            $("#selectschedule option").remove();
                            //add a blank option
                            $("#selectschedule").append('<option></option>');
                            //append new options returned
                            for (var i = result.length - 1; i >= 0; i--) {
                                $("#selectschedule").append('<option>'+ result[i].schedule_name +'</option>');
                            };
                        },
        });
    });
});
</script>

HTML

<table width="100%" class="table">
   <tr>
      <td class="align-middle" style="width: 50%;">
         <label for="#selectyear" value="calendar_year" style="width:100%">
            <span class="small pl-1">Select Calendar Year</span>
            <select class="form-control" name="selectyear" id="selectyear">
               <option value="blank"></option>
                  {% for schedule in schedules|dictsort:'fee_schedule_calendar_year' %}
                     {% ifchanged %}<!--used to only show unique values-->
                     <option value="{{ schedule.fee_schedule_calendar_year }}">{{ schedule.fee_schedule_calendar_year }}</option>
                     {% endifchanged %}     
                  {% endfor %}
            </select>
         </label>
      </td>
      <td class="align-middle" style="width: 50%;">
         <label for="#selectschedule" value="fee_schedule" style="width: 100%;">
         <span class="small pl-1">Select Fee Schedule</span>
            <select class="form-control" name="selectschedule" id="selectschedule"></select>
         </label>
      </td>
   </tr>
</table>

Views.py

# Handle AJAX request for fee schedule calendar year select
def getdetails(request, file_upload_id, file_header_id):
    schedule_year = json.loads(request.GET.get('year'))
    result_set = []
    schedules = FeeSchedule.objects.filter(fee_schedule_calendar_year=schedule_year)
    for schedule in schedules:
        result_set.append({'schedule_name': schedule.fee_schedule_name})
    return HttpResponse(json.dumps(result_set, indent=4, sort_keys=True, default=str), content_type='application/json')

urls.py

path('whatever_your_current_path_is_for_this_view/getdetails/', login_required(views.getdetails), name='get_details'),
1

我对那些不够简洁的解决方案感到厌烦,所以我写了一个可能适合大多数情况的灵活工具:

django-related-select

现在这个工具只支持在线/AJAX相关的选择框。我计划在不久的将来(可能是这周或下周)增加一个离线模式,这个模式会在小部件中加入一些渲染好的JavaScript代码,用来跟踪父选择框的变化,并通过一个值到选项列表的映射,把这些变化传递给子选择框。AJAX解决方案非常适合像汽车品牌/型号这种有成千上万选项的情况,而离线解决方案则更适合产品/颜色这种可能只有几十个选项的情况。

2

你可以使用Jquery的一个插件,叫做chained。

示例链接: http://codepen.io/anon/pen/EapNPo?editors=101

HTML部分

<select id="id_country" name="country">
    <option value="" selected="selected">---------</option>
    <option value="1">Colombia</option>
    <option value="2">Rusia</option>
</select>
<select id="id_city" name="city">
    <option value="" selected="selected">---------</option>
    <option value="1" class="1">Bogotá</option>
    <option value="2" class="2">Moscú</option>
    <option value="3" class="2">San Petersburgo</option>
    <option value="4" class="1">Valledupar</option>
</select>

JavaScript部分

$("#id_city").chained("#id_country");

这个插件可以用来生成带有模型的表单(外键)。

想要了解更多,可以去看这个完整的教程: https://axiacore.com/blog/django-y-selects-encadenados/

28

好吧,我为你写了一个完整的项目,希望这能帮到你 :) :
在这个项目中,我们有一些国家,每个国家都有很多城市。
如图所示,每当你选择一个国家时,下面的下拉框只会显示与该国家相关的城市 :)

伊朗的城市

美国的城市

好了,现在我们来看代码吧。
(完整的项目源代码在我的 github 上 : https://github.com/nodet07/Django-Related-DropDowns
models.py :
只有两个简单的模型,一个国家可以有很多城市!

 from django.db import models
    class City(models.Model):
        name = models.CharField(max_length=50)
        country = models.ForeignKey("Country")
        def __unicode__(self):
            return u'%s' % (self.name)

    class Country(models.Model):
        name = models.CharField(max_length=50)
        def __unicode__(self):
            return u'%s' % (self.name)

views.py:

from django.shortcuts import render
from map.models import *
from django.utils import simplejson
from django.http import HttpResponse

def index(request):
    countries = Country.objects.all()
    print countries
    return render(request, 'index.html', {'countries': countries})

def getdetails(request):
    #country_name = request.POST['country_name']
    country_name = request.GET['cnt']
    print "ajax country_name ", country_name

    result_set = []
    all_cities = []
    answer = str(country_name[1:-1])
    selected_country = Country.objects.get(name=answer)
    print "selected country name ", selected_country
    all_cities = selected_country.city_set.all()
    for city in all_cities:
        print "city name", city.name
        result_set.append({'name': city.name})
    return HttpResponse(simplejson.dumps(result_set), mimetype='application/json',     content_type='application/json')

index.html :

<html>
    <head>
    <script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
    <script type="text/javascript" src="http://yourjavascript.com/7174319415/script.js"></script>
        <script>
            $(document).ready(function(){
                 $('select#selectcountries').change(function () {
                     var optionSelected = $(this).find("option:selected");
                     var valueSelected  = optionSelected.val();
                     var country_name   = optionSelected.text();


                     data = {'cnt' : country_name };
                     ajax('/getdetails',data,function(result){

                            console.log(result);
                            $("#selectcities option").remove();
                            for (var i = result.length - 1; i >= 0; i--) {
                                $("#selectcities").append('<option>'+ result[i].name +'</option>');
                            };


                         });
                 });
            });
        </script>
    </head>

    <body>
        <select name="selectcountries" id="selectcountries">
        {% for item in countries %}
            <option val="{{ item.name }}"> {{ item.name }} </option>    
        {% endfor %}
        </select>   


        <select name ="selectcities" id="selectcities">


        </select>

    </body>
</html>

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