将每个XML节点提取到单独的文本文件中

Question

我有一个这样的xml文件：

<root>
    <article>
        <article_taxonomy></article_taxonomy>
        <article_place>Somewhere</article_place>
        <article_number>1</article_number>
        <article_date>2001</article_date>
        <article_body>Blah blah balh</article_body>
    </article>

    <article>
        <article_taxonomy></article_taxonomy>
        <article_place>Somewhere</article_place>
        <article_number>2</article_number>
        <article_date>2001</article_date>
        <article_body>Blah blah balh</article_body>
    </article>

    ...
    ...
    more nodes

</root> 

我想做的是把每一个节点（从<article>到</article>标签之间的内容）提取出来，并写入一个单独的txt或xml文件。我还想保留这些标签。

有没有办法做到这一点，而不使用正则表达式？有没有什么建议？

Answer 1

试试这样做：

from xml.dom import minidom
xmlfile = minidom.parse('yourfile.xml')
#for example for 'article_body'
article_body = xmlfile.getElementsByTagName('article_body') 

或者

import xml.etree.ElementTree as ET
xmlfile = ET.parse('yourfile.xml')
root_tag = xmlfile.getroot()
for each_article in root_tag.findall('article'):
   article_taxonomy = each_article.find('article_taxonomy').text
   article_place = each_article.find('article_place').text
   # etc etc

Answer 2

这里有一种方法可以使用 ElementTree 来实现：

import xml.etree.ElementTree as ElementTree

def main():
    with open('data.xml') as f:
        et = ElementTree.parse(f)
        for article in et.findall('article'):
            xml_string = ElementTree.tostring(article)
            # Now you can write xml_string to a new file
            # Take care to name the files sequentially

if __name__ == '__main__':
    main()