运行一个非常简单的Python程序时遇到问题

2 投票
2 回答
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提问于 2025-04-15 14:50

为什么我的程序在这里出错了?

import random

TheNumber = random.randrange(1,200,1)
NotGuessed = True
Tries = 0

GuessedNumber = int(input("Take a guess at the magic number!: "))                 

while NotGuessed == True:
    if GuessedNumber < TheNumber:
        print("Your guess is a bit too low.")
        Tries = Tries + 1
        GuessedNumber = int(input("Take another guess at the magic number!: "))

    if GuessedNumber > TheNumber:
        print("Your guess is a bit too high!")
        Tries = Tries + 1
        GuessedNumber = int(input("Take another guess at the magic number!: "))

    if GuessedNumber == TheNumber:
        print("You've guess the number, and it only took you " + string(Tries) + "!")

错误出现在最后一行。我该怎么办?

补充:

另外,为什么我在Python中不能使用Tries++?难道没有自动递增的代码吗?

补充 2:错误是:

Traceback (most recent call last):
  File "C:/Users/Sergio/Desktop/GuessingGame.py", line 21, in <module>
    print("You've guess the number, and it only took you " + string(Tries) + "!")
NameError: name 'string' is not defined

2 个回答

3

在你最后一行,把 string 替换成 str -- 这样应该能解决 Python 报错的问题,至少是这样。

2

这里用的是 str,而不是 string。不过,你的无限循环才是更大的问题。自动递增的写法是这样的:

Tries += 1

总的来说,你可以稍微改进一下你的代码:

the_number = random.randrange(1,200,1)
tries = 1

guessed_number = int(input("Take a guess at the magic number!: ")) 
while True:
    if guessed_number < the_number:
        print("Your guess is a bit too low.")

    if guessed_number > the_number:
        print("Your guess is a bit too high!")

    if guessed_number == the_number:
        break
    else:
        guessed_number = int(input("Take another guess at the magic number!: "))
        tries += 1

print("You've guessed the number, and it only took you %d tries!" % tries)

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