Flask UnboundField 查询选择字段
我在Flask中遇到了关于QuerySelectFields的问题:
class User(db.Model):
id = db.Column(db.Integer, primary_key = True)
username = db.Column(db.String(64), unique = True)
clearname = db.Column(db.String(254))
password = db.Column(db.String(254))
role = db.Column(db.Integer)
def __init__(self, username, clearname, password, role):
self.username = username
self.clearname = clearname
self.password = password
self.role = role
def __repr__(self):
return 'Benutzer %r' % self.username
def get_User():
return db.session.query(User.username).all()
class f1(Form):
us = QuerySelectField(u'hello', query_factory = get_User())
我能看到我的用户('Admin'和'test1'),但它们没有出现在选择框里。我得到的只是:
<UnboundField(QuerySelectField, (u'hello',), {'query_factory': [(u'Admin',), (u'test1',)]})>
我该如何正确创建一个QuerySelectField?
有人能帮忙吗?
谢谢!
编辑 2014-08-18: 视图包含:
return render_template('login.html',
title = 'Sign In',
form = form)
编辑 2014-08-18:
首先:感谢你的回复!
与此同时,我有了一些小进展——这是代码(基于Flask Mega-Tutorial):
run.py:
#!env/bin/python
from app import app
app.run(debug = True)
app/init.py:
from flask import Flask
from flask.ext.sqlalchemy import SQLAlchemy
app = Flask(__name__)
app.config.from_object('config')
db = SQLAlchemy(app)
from app import views, models
app/models.py:
from app import db
ROLE_USER = 100
ROLE_ADMIN = 0
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key = True)
username = db.Column(db.String(64), index = True, unique = True)
clearname = db.Column(db.String(64))
password = db.Column(db.String(256))
role = db.Column(db.SmallInteger, default = ROLE_USER)
def __repr__(self):
return '<User %r>' % (self.username)
def get_User():
return User.query
app/forms.py:
from flask.ext.wtf import Form
from wtforms import TextField, BooleanField
from wtforms.validators import Required
from wtforms.ext.sqlalchemy.fields import QuerySelectField
from .models import get_User
class LoginForm(Form):
openid = TextField('openid', validators = [Required()])
remember_me = BooleanField('remember_me', default = False)
user = QuerySelectField(u'User', query_factory=get_User)
app/views.py:
from flask import render_template, flash, redirect
from app import app
from .forms import LoginForm
@app.route('/')
@app.route('/index')
def index():
return "Hello, World!"
@app.route('/login')
def login():
form = LoginForm()
return render_template('login.html', title='Eingloggen!', form=form)
app/templates/login.html:
<!-- extend from base layout -->
{% extends "base.html" %}
{% block content %}
<h1>Sign In</h1>
<form action="" method="post" name="login">
{{form.hidden_tag()}}
<p>
Please enter your OpenID:<br>
{{form.openid(size=80)}}<br>
</p>
<p>{{form.remember_me}} Remember Me</p>
<p>{{form.user}} The QuerySelectField :-)</p>
<p><input type="submit" value="Sign In"></p>
</form>
{% endblock %}
现在QuerySelectField显示了我的User类的__repr__
:
----------------
| <User 'test1'> |
| <User 'Admin'> |
----------------
select id="user" name="user"><option value="1"><User 'test1'></option><option value="2"><User 'Admin'></option></select>
但是我该如何像select * from username
那样查询,并在选择框中显示用户名'test1'和'Admin'而不改变__repr__
呢?
如果我想进行另一个查询,比如select * from role
,我想要一些函数,比如get_User()、get_Roles()……把这些函数放在class User
里面是个好主意吗?
2 个回答
0
这个 query_factory 回调函数应该返回完整的实体,也就是书籍,而不是书籍的 ID。我觉得 QuerySelectField 可能在尝试把查询的结果当作已经映射好的对象来使用,但实际上返回的只是 ID(以 KeyedTuple 实例的形式)。
我认为这样写回调函数是正确的:
def get_User():
return User.query
0
只需要把最后一行的 get_user 后面的 () 去掉就行了。
def get_User():
return db.session.query(User.username).all # <----