Flask UnboundField 查询选择字段

0 投票
2 回答
2013 浏览
提问于 2025-04-18 17:17

我在Flask中遇到了关于QuerySelectFields的问题:

class User(db.Model):
        id = db.Column(db.Integer, primary_key = True)
        username = db.Column(db.String(64), unique = True)
        clearname = db.Column(db.String(254))
        password = db.Column(db.String(254))
        role = db.Column(db.Integer)

        def __init__(self, username, clearname, password, role):
                self.username = username
                self.clearname = clearname
                self.password = password
                self.role = role

        def __repr__(self):
                return 'Benutzer %r' % self.username

def get_User():
        return db.session.query(User.username).all()


class f1(Form):
        us = QuerySelectField(u'hello', query_factory = get_User())

我能看到我的用户('Admin'和'test1'),但它们没有出现在选择框里。我得到的只是:

<UnboundField(QuerySelectField, (u'hello',), {'query_factory': [(u'Admin',), (u'test1',)]})> 

我该如何正确创建一个QuerySelectField?

有人能帮忙吗?

谢谢!

编辑 2014-08-18: 视图包含:

   return render_template('login.html', 
        title = 'Sign In',
        form = form)

编辑 2014-08-18:

首先:感谢你的回复!

与此同时,我有了一些小进展——这是代码(基于Flask Mega-Tutorial):

run.py:

#!env/bin/python
from app import app
app.run(debug = True)

app/init.py:

from flask import Flask
from flask.ext.sqlalchemy import SQLAlchemy

app = Flask(__name__)
app.config.from_object('config')
db = SQLAlchemy(app)

from app import views, models

app/models.py:

from app import db

ROLE_USER = 100
ROLE_ADMIN = 0

class User(db.Model):
    __tablename__ = 'users'
    id = db.Column(db.Integer, primary_key = True)
    username = db.Column(db.String(64), index = True, unique = True)
    clearname = db.Column(db.String(64))
    password = db.Column(db.String(256))
    role = db.Column(db.SmallInteger, default = ROLE_USER)

    def __repr__(self):
        return '<User %r>' % (self.username)


def get_User():
    return User.query

app/forms.py:

from flask.ext.wtf import Form
from wtforms import TextField, BooleanField
from wtforms.validators import Required
from wtforms.ext.sqlalchemy.fields import QuerySelectField

from .models import get_User

class LoginForm(Form):
    openid = TextField('openid', validators = [Required()])
    remember_me = BooleanField('remember_me', default = False)
    user = QuerySelectField(u'User', query_factory=get_User)

app/views.py:

from flask import render_template, flash, redirect
from app import app
from .forms import LoginForm

@app.route('/')
@app.route('/index')
def index():
    return "Hello, World!"


@app.route('/login')
def login():
    form = LoginForm()
    return render_template('login.html', title='Eingloggen!', form=form)

app/templates/login.html:

<!-- extend from base layout -->
{% extends "base.html" %}

{% block content %}
<h1>Sign In</h1>
<form action="" method="post" name="login">
    {{form.hidden_tag()}}
    <p>
        Please enter your OpenID:<br>
        {{form.openid(size=80)}}<br>
    </p>
    <p>{{form.remember_me}} Remember Me</p>
    <p>{{form.user}} The QuerySelectField :-)</p>
    <p><input type="submit" value="Sign In"></p>
</form>
{% endblock %}

现在QuerySelectField显示了我的User类的__repr__

 ----------------
| <User 'test1'> |
| <User 'Admin'> |
 ----------------
select id="user" name="user"><option value="1">&lt;User 'test1'&gt;</option><option value="2">&lt;User 'Admin'&gt;</option></select>

但是我该如何像select * from username那样查询,并在选择框中显示用户名'test1'和'Admin'而不改变__repr__呢?

如果我想进行另一个查询,比如select * from role,我想要一些函数,比如get_User()、get_Roles()……把这些函数放在class User里面是个好主意吗?

2 个回答

0

这个 query_factory 回调函数应该返回完整的实体,也就是书籍,而不是书籍的 ID。我觉得 QuerySelectField 可能在尝试把查询的结果当作已经映射好的对象来使用,但实际上返回的只是 ID(以 KeyedTuple 实例的形式)。

我认为这样写回调函数是正确的:

def get_User():
    return User.query
0

只需要把最后一行的 get_user 后面的 () 去掉就行了。

def get_User():
    return db.session.query(User.username).all # <----

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