如何根据第一个列表框的选择生成第二个列表框?

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2 回答
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提问于 2025-04-18 15:24

我有三个列表框,第一个列表框里有一些选项。当用户选择一个选项后,第二个列表框需要根据之前的选择来填充内容。下面是我尝试过的代码。我使用的是Python 2.7。

import sys
import Tkinter as TK

font = ('Times New Rome', 12, 'Bold')
Template = ''
Entrybox1 = ''
Entrybox2 = ''
Lb1 = ''
Lb2 = ''
Lb3 = ''

class smartstopkiosk_tk(TK.Tk):
    def __init__(self, parent):
        TK.Tk.__init__(self,parent)
        self.parent = parent
        self.initialize()
    
    def initialize(self):
        self.grid()
        #self.parent.title("Smartstop Kiosk")
        global Entrybox1
        global Entrybox2
        global LocalTemplate
        global Software
        seltext = ""
        software = ('Microsoft', 'Abode', 'SAP', 'Lotus  Notes', 'Jive','Cisco',     'Chrome')
        hardware = ("Computer",  "Charger", " USB Headset", "Keyboard", "Mouse", "Webcam")
        microsoft = ("Outlook", "Lync", "Word", "Excel", "PowerPoint", "Visio", "Project", "Publisher")
        adobe = ("Adobe Reader", "Java", "Flash", "Adobe Pro")
        cisco = ('IP Communicator', '')
        wireless = ("MYLOW",  "Corporate", "Visitor", "MYLTW")
        printers  = ("2N", "2S", "3N", "3S", "4N",  "4S",  "5N", "5S")      
        mobile =  ("Blackberry", "iPhone","iPad")
        AD  = ("Unlock", "Reset")
        LocalTemplate = ('User Assistance with Software.', 'User Assistance with       Hardware.', 'Mobile Device Support.',
        'Software Installation Request', 'Hardware Request', 'Wireless Connection',   'Password Reset/Username Unlocked', 
        'Add Printer')

         #creates font types
         font = ('Times New Roman', 14, 'bold')
         font2 = ('Times New Roman',12, 'bold')
    
         #Creates Instructions for Users
         stepOne = TK.LabelFrame(self, text=" 1. User Information: ", font = font2)
         stepOne.grid(row=0, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5,   ipady=5)
         stepTwo = TK.LabelFrame(self, text="2. Select Program or Hardware Problems", font = font2)
         stepTwo.grid(row=3, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5, ipady=5)
         stepThree = TK.LabelFrame(self, text="Please Enter the Problem or Your Request:", font = font2)
         stepThree.grid(row=6, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5, ipady=5)
    
         #Creates Label for Users
         Label1 = TK.Label(stepOne, text = "First Name", font = font)
         Label1.grid(column = 2, row = 0, sticky = 'w', padx = (10, 10))
         Label2 = TK.Label(stepOne, text = "Last Name", font = font)
         Label2.grid(column = 4, row = 0, sticky = 'w', padx = (10, 10))
         Label3 = TK.Label(stepOne, text = "UserName", font = font)
         Label3.grid(column = 6, row = 0, sticky = 'w', padx = (10, 10))
    
         #Creates Entry Box for User input
         self.entry = TK.Entry(stepOne, width = 30)
         self.entry.grid(column = 2, row = 1,padx = (10, 10))
         entry2 = TK.Entry(stepOne, width = 30)
         entry2.grid(column = 4, row = 1,padx = (10, 10))
         entry3 = TK.Entry(stepOne, width = 30)
         entry3.grid(column = 6, row = 1, columnspan = 2, padx = (10, 10))
    
         #Creates User Input Box
         Usertext = TK.Text(stepThree, height = 10, width = 110, font = font)
         Usertext.grid(column = 2, row = 15, padx = (10, 10))
    
         #Creates List Boxes
         Listbox1 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font   = font, exportselection = 0)
         Listbox1.grid(column = 2, row = 1, padx = (10, 10))
         for i in LocalTemplate:
             Listbox1.insert(TK.END, i)
         Listbox1.bind("<<ListboxSelect>>", self.selection)
         Listbox2 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font, exportselection = 0)
         Listbox2.grid(column = 4, row = 1, padx = (10, 10))
         for x in seltext:
             Listbox2.insert(TK.END, x)
         Listbox2.bind("<<ListboxSelect>>", self.selection)
         Listbox3 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font, exportselection = 0)
         Listbox3.grid(column = 6, row = 1, padx = (10, 10))
    
         #Creates Buttons
         Submit = TK.Button(self, text = 'Submit', font = font2)
         Submit.grid(column = 3, row = 10, sticky = 'we', padx = (10, 10))
         Startover = TK.Button(self, text = 'Cancel', font = font2)
         Startover.grid(column = 4, row = 10, sticky = 'we', padx = (10, 10))
    
         def selection(self, val):
         sender = val.Listbox1
         index = listbox1.curselection()
         value = Listbox1.get(index[0])
         if index == 1 or index == 4:
             seltext = software
         elif index == 2 or index == 5:
             seltext = hardware
         elif index == 3:
             seltext = mobile
         elif index == 6:
             seltext = wireless
         elif index == 7:
             seltext = AD
         elif index == 8:
             seltext = printer

def main():
    app = smartstopkiosk_tk(None)
    app.geometry("1300x768")

    app.mainloop()
    
if __name__ == "__main__":
    main()

我一直收到这个错误信息:回溯(Traceback) 文件 "C:\python27\lib\lib-tk\Tkinter.py",第1845行,在 getattr 中 返回 getattr(self.tk, attr) AttributeError: selection

更新! 这是我如何在第一个列表框中添加文本,并根据你的选择填充第二个列表框的方法。

    def getchoice(event):
        seltext = ''
        INDEX = Listbox1.curselection()
        if INDEX == (0,) or INDEX == (4,):
            seltext = software
        elif INDEX == (1,) or INDEX == (5,):
            seltext = hardware
            
        elif INDEX == (2,):
            seltext = mobile
    
        elif INDEX == (3,):
            seltext = wireless
    
        elif INDEX == (6,):
            seltext = AD
        
        elif INDEX == (7,):
            seltext = printers
        print INDEX
        Listbox2.delete(0, TK.END)
        for x in seltext:
            Listbox2.insert(TK.END, x)  

        #Creates List Boxes
    Listbox1 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font, exportselection = 0)
    Listbox1.grid(column = 2, row = 1, padx = (10, 10))
    for x in LocalTemplate:
        Listbox1.insert(TK.END, x)
    Listbox1.bind("<<ListboxSelect>>", getchoice)
    Listbox2 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font, exportselection = 0)
    Listbox2.grid(column = 4, row = 1, padx = (10, 10))
    Listbox2.bind("<<ListboxSelect>>", getchoice2)
    Listbox3 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font, exportselection = 0)
    Listbox3.grid(column = 6, row = 1, padx = (10, 10))

2 个回答

0

这一行代码是问题所在,虽然错误信息可能已经告诉你了:

value = widget.get(selection[0])

你没有名为 selection 的变量。也许你是想用 index[0],而不是 selection[0],因为你在前面一行已经定义了 index

当然,你也会遇到类似的问题,因为 widget 也是未定义的。

0

好的,@Jobes23,这个过程很有趣。不过你的代码里有几个“小白错误”:一开始你定义了 lbl123,但却用了 label123,这样 lbl1 就没用了。还有一些多余的变量和代码。此外,在设置列表框的变量时,你有时用了 '',有时用了 "" 来包围文字,这虽然不影响代码运行,但保持一致的写法会更好。正如 Bryan Oakley 所说,你的代码看起来像是把各处的代码片段拼凑在一起,而没有考虑它们单独和一起是怎么工作的——理解代码是解决问题的关键。我尝试去掉了一些多余的代码,但不确定你到底需要多少。

我之前说过 self.selection 不是一个选项,所以我去掉了 listbox.bind(...),而是做了一个按钮,按钮的命令指向一个函数,这个函数会获取选中的选项,并用这个结果把第二个列表框设置为一个字符串,我想这正是你想要实现的。

import Tkinter as TK

class smartstopkiosk_tk(TK.Tk):
    def __init__(self, parent):
        TK.Tk.__init__(self,parent)
        self.parent = parent
        self.initialize()

    def initialize(self):
        self.grid()
        #self.parent.title("Smartstop Kiosk")
        software = ('Microsoft', 'Abode', 'SAP', 'Lotus  Notes', 'Jive','Cisco', 'Chrome')
        hardware = ("Computer",  "Charger", " USB Headset", "Keyboard", "Mouse", "Webcam")
        microsoft = ("Outlook", "Lync", "Word", "Excel", "PowerPoint", "Visio", "Project", "Publisher")
        adobe = ("Adobe Reader", "Java", "Flash", "Adobe Pro")
        cisco = ('IP Communicator', '')
        wireless = ("MYLOW",  "Corporate", "Visitor", "MYLTW")
        printers  = ("2N", "2S", "3N", "3S", "4N",  "4S",  "5N", "5S")
        mobile =  ("Blackberry", "iPhone","iPad")
        AD  = ("Unlock", "Reset")
        LocalTemplate = ('User Assistance with Software', 'User Assistance with Hardware', 'Mobile Device Support', 'Software Installation Request', 'Hardware Request', 'Wireless Connection', 'Password Reset/Username Unlocked',
    'Add Printer')
        def getchoice2():
            print
            # use same method to find out which of the second list is chosen, and carry on.

        def getchoice():
            seltext = ''
            INDEX = Listbox1.curselection()
            if INDEX == ('0',) or INDEX == ('4',):
                seltext = software
            if INDEX == ('1',) or INDEX == ('5',):
                seltext = hardware
            if INDEX == ('2',):
                seltext = mobile
            if INDEX == ('3',):
                seltext = wireless
            if INDEX == ('6',):
                seltext = AD
            if INDEX == ('7',):
                seltext = printers
            selectchoice.config(command = getchoice2)
            for x in seltext:
                Listbox2.insert(TK.END, x)


        #creates font types
        font = ('Times New Roman', 14, 'bold')
        font2 = ('Times New Roman',12, 'bold')
        #Creates Instructions for Users
        stepOne = TK.LabelFrame(self, text=" 1. User Information: ", font = font2)
        stepOne.grid(row=0, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5,   ipady=5)
        stepTwo = TK.LabelFrame(self, text="2. Select Program or Hardware Problems", font = font2)
        stepTwo.grid(row=3, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5, ipady=5)
        stepThree = TK.LabelFrame(self, text="Please Enter the Problem or Your Request:", font = font2)
        stepThree.grid(row=6, columnspan=7, sticky='w', padx=5, pady=5, ipadx=5, ipady=5)
        #Creates Label for Users
        Label1 = TK.Label(stepOne, text = "First Name", font = font)
        Label1.grid(column = 2, row = 0, sticky = 'w', padx = (10, 10))
        Label2 = TK.Label(stepOne, text = "Last Name", font = font)
        Label2.grid(column = 4, row = 0, sticky = 'w', padx = (10, 10))
        Label3 = TK.Label(stepOne, text = "Mylan UserName", font = font)
        Label3.grid(column = 6, row = 0, sticky = 'w', padx = (10, 10))
        #Creates Entry Box for User input
        self.entry = TK.Entry(stepOne, width = 30)
        self.entry.grid(column = 2, row = 1,padx = (10, 10))
        entry2 = TK.Entry(stepOne, width = 30)
        entry2.grid(column = 4, row = 1,padx = (10, 10))
        entry3 = TK.Entry(stepOne, width = 30)
        entry3.grid(column = 6, row = 1, columnspan = 2, padx = (10, 10))
        #Creates User Input Box
        Usertext = TK.Text(stepThree, height = 10, width = 110, font = font)
        Usertext.grid(column = 2, row = 15, padx = (10, 10))
        #Creates List Boxes
        Listbox1 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font   = font)
        Listbox1.grid(column = 2, row = 1, padx = (10, 10))
        for i in LocalTemplate:
            Listbox1.insert(TK.END, i)
        Listbox2 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font)
        Listbox2.grid(column = 4, row = 1, padx = (10, 10))
        Listbox3 = TK.Listbox(stepTwo, selectmode = 'SINGLE', height = 10, width = 35, font = font)
        Listbox3.grid(column = 6, row = 1, padx = (10, 10))
        #Creates Buttons
        selectchoice = TK.Button(self, text = 'select my choice', font = font2, command = getchoice)
        selectchoice.grid(row = 5, column = 1, sticky = 'we', padx = (10, 10))
        Submit = TK.Button(self, text = 'Submit', font = font2)
        Submit.grid(column = 3, row = 10, sticky = 'we', padx = (10, 10))
        Startover = TK.Button(self, text = 'Cancel', font = font2)
        Startover.grid(column = 4, row = 10, sticky = 'we', padx = (10, 10))

def main():
    app = smartstopkiosk_tk(None)
    app.geometry("1300x768")
    app.mainloop()

if __name__ == "__main__":
    main()

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