Python - Elementtree - 使用变量在树中搜索

4 投票
2 回答
2749 浏览
提问于 2025-04-18 15:12

我有一个包含很多化学基团及其属性的xml文件。下面是这个文件的一部分:

 <groups>
  <group name='CH3'>
   <mw>15.03502</mw>
   <heatCapacity>
    <a>19.5</a>
   </heatCapacity>
  </group>
  <group name='CH2'>
   <mw>14.02708</mw>
   <heatCapacity>
    <a>-0.909</a>
   </heatCapacity>
  </group>
  <group name='COOH'>
   <mw>45.02</mw>
   <heatCapacity>
    <a>-24.1</a>
   </heatCapacity>
   </heatCapacity>
  </group>
  <group name='OH'>
   <mw>17.0073</mw>
   <heatCapacity>
    <a>25.7</a>
   </heatCapacity>
  </group>
<\groups>

在我的Python代码中,我使用ElementTree来解析这个文件。我有一个列表 blocks=['CH3','CH2'],我想用这个列表来找到这两个基团。我尝试了以下代码:

import elementtree.ElementTree as ET
document = ET.parse( 'groups.xml' )
blocks=['CH3','CH2']
for item in blocks:
   group1 = document.find(item)
   print group1

但是我得到的结果都是'None'。你能帮我一下吗?

非常感谢

2 个回答

2

试试这个:

for block in blocks:
    group = document.find('./group[@name="{}"]'.format(block))
    if group:
        xml.etree.ElementTree.dump(group)
    else:
        print "Group {} not found.".format(group)
3

你可以通过一个元素的 .get() 方法来找到它的属性。这里有一种查看属性的方法:

import xml.etree.ElementTree as ET
document = ET.parse( 'groups.xml' )
blocks=['CH3','CH2']
for group in document.getroot():
   if group.get('name') in blocks:
     print group

如果你需要根据特定的选择条件来访问数据,你可以自己创建一个字典:

import xml.etree.ElementTree as ET

# Parse
document = ET.parse( 'groups.xml' )

# Add a dictionary so that <group>s
# are easy to find by name
groups = {}
for group in document.getroot():
   groups[group.get('name')] = group

# Look up our compounds in the dictionary
blocks=['CH3', 'CH2']
for item in blocks:
    group = groups[item]
    mw = group.find('mw').text
    print item, mw

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