循环问题剪刀石头布游戏

Question

我刚开始学习编程。
我需要为我的编程入门课写一个剪刀石头布的游戏。我已经有了一个不错的开头，但有一些问题我不知道怎么解决。

我需要三个不同的菜单。主菜单应该问你要 1. 开始新游戏 2. 加载游戏或 3. 退出。选择 1 或 2 后，你需要输入你的名字，然后游戏就开始了。接下来会让你选择 1. 石头 2. 布 3. 剪刀。我的游戏运行得很好，但在选择石头、布或剪刀后，我想弹出一个新的菜单：你想做什么？1. 再玩一次 2. 查看统计信息 3. 退出。但我不知道把这个放在哪里。我试过几个不同的地方，但它就是跳过这个菜单，直接又问我选择石头、布或剪刀。

然后我的第二个问题是，当用户选择 1. 开始新游戏时，需要询问他们的名字，并用这个名字把他们的游戏保存到一个文件里。然后当用户选择 2. 加载游戏时，他们的名字会用来找到一个文件 "名字.rps"，并加载他们的统计信息继续游戏（统计信息、回合数、名字）。

任何帮助都非常感谢。

import random
import pickle

tie = 0
pcWon = 0
playerWon = 0
game_round = (tie + playerWon + pcWon) + 1

# Displays program information, starts main play loop
def main():
    print("Welcome to a game of Rock, Paper, Scissors!")
    print("What would you like to do?")
    print ("")
    welcomemenu()
    playGame = True
    while playGame:
        playGame = play()
    displayScoreBoard()
    prompt = input("Press enter to exit")

def welcomemenu():
    print ("[1]: Start New Game")
    print ("[2]: Load Game")
    print ("[3]: Quit")
    print("")
    menuselect = int(input("Enter choice: "))
    print("")
    if menuselect == 1:
        name = input("What is your name? ")
        print("Hello", name, ".")
        print("Let's play!")
    elif menuselect == 2:
        name = input("What is your name? ")
        print("Welcome back", name, ".")
        print("Let's play!")
        player_file = open('name.rps', 'wb')
        pickle.dump(name, player_file)
        player_file.close()
    elif menuselect == 3:
        exit()
    return menuselect


# displays the menu for user, if input ==4, playGame in the calling function (main()) is False, terminating the program.
# Generate a random int 1-3, evaluate the user input with the computer input, update globals accordingly, returning True
# to playGame, resulting in the loop in the calling function (main()) to continue.
def play():
    playerChoice = int(playerMenu())
    if playerChoice == 4:
        return 0
    else:
        pcChoice = pcGenerate()
        outcome = evaluateGame(playerChoice, pcChoice)
        updateScoreBoard(outcome)
        return 1


# prints the menu, the player selects a menu item, the input is validated, if the input is valid, returned the input, if
# the input is not valid, continue to prompt for a valid input
# 1 - rock
# 2 - paper
# 3 - scissors

def playerMenu():
    print("Select a choice: \n [1]: Rock \n [2]: Paper \n [3]: Scissors")
    print("")
    menuSelect = input("What will it be? ")
    while not validateInput(menuSelect):
        invalidChoice(menuSelect)
        menuSelect = input("Enter a correct value: ")

    return menuSelect


# if the user doesn't input a 1-3 then return false, resulting in prompting the user for another value. If the value
# is valid, return True
# takes 1 argument
# menuSelection - value user entered prior
def validateInput(menuSelection):
    if menuSelection == "1" or menuSelection == "2" or menuSelection == "3":
        return True
    else:
        return False


# return a random integer 1-3 to determine pc selection
# 1 - rock
# 2 - paper
# 3 - scissors
def pcGenerate():
    pcChoice = random.randint(1,3)
    return pcChoice


# evaluate if the winner is pc or player or tie, return value accordingly
# 0 - tie
# 1 - player won
# -1 - pc won
def evaluateGame(playerChoice, pcChoice):
    if playerChoice == 1:
        print("You have chosen rock.")
        if pcChoice == 1:
            #tie
            print("Computer has chose rock as well. TIE!")
            return 0
        elif pcChoice == 2:
            #paper covers rock - pc won
            print("The computer has chosen paper. Paper covers rock. You LOSE!")
            return -1
        else:
            #rock breaks scissors - player won
            print("The computer has chosen scissors. Rock breaks scissors. You WIN!")
            return 1
    elif playerChoice == 2:
        print("You have chosen paper.")
        if pcChoice == 1:
            #paper covers rock - player won
            print("The computer has chosen rock. Paper covers rock. You WIN!")
            return 1
        elif pcChoice == 2:
            #tie
            print("The computer has chosen paper as well. TIE!")
            return 0
        else:
            #scissors cut paper - pc won
            print("The computer has chosen scissors. Scissors cut paper. You LOSE!")
            return -1
    else: #plyer choice defaults to 3
        print("You have chosen scissors")
        if pcChoice == 1:
            #rock breaks scissors - pc won
            print("The computer has chosen rock. Rock breaks scissors. You LOSE!")
            return -1
        elif pcChoice == 2:
            #scissors cut paper - player won
            print("The computer has chosen paper. Scissors cut paper. You WIN!")
            return 1
        else: #pc defaults to scissors
            #tie
            print("The computer has chosen scissors as well. TIE!")
            return 0



# Update track of ties, player wins, and computer wins
def updateScoreBoard(gameStatus):
    global tie, playerWon, pcWon
    if gameStatus == 0:
        tie +=1
    elif gameStatus == 1:
        playerWon += 1
    else:
        pcWon += 1


# If user input is invalid, let them know.
def invalidChoice(menuSelect):
    print(menuSelect, "is not a valid option. Please use 1-3")


# Print the scores before terminating the program.
def displayScoreBoard():
    global tie, playerWon, pcWon
    print("Statistics:\nTies:", tie, "\nPlayer Wins:", playerWon, "\nComputer Wins:", pcWon)
    print("Win/Loss Ratio:", playerWon/pcWon)
    print("Rounds:", tie + playerWon + pcWon)

main()

用户输入循环控制文件操作菜单设计游戏开发变量存储编程入门统计信息

循环问题剪刀石头布游戏

4 个回答

下面是剧透代码

撰写回答

循环问题 剪刀石头布游戏

4 个回答

下面是剧透代码

撰写回答

循环问题剪刀石头布游戏