PYTHONPATH -bash: export: `myproject/tornado_main.py': 不是有效的标识符
我正在尝试学习这个叫做django-tornado-demo的项目,地址在这里:https://github.com/bdarnell/django-tornado-demo。我需要运行一个可执行文件,下面是相关的代码:
#!/usr/bin/env python
# Run this with
# PYTHONPATH=. DJANGO_SETTINGS_MODULE=testsite.settings testsite/tornado_main.py
# Serves by default at
# http://localhost:8080/hello-tornado and
# http://localhost:8080/hello-django
from tornado.options import options, define, parse_command_line
import django.core.handlers.wsgi
import tornado.httpserver
import tornado.ioloop
import tornado.web
import tornado.wsgi
define('port', type=int, default=8080)
class HelloHandler(tornado.web.RequestHandler):
def get(self):
self.write('Hello from tornado')
def main():
parse_command_line()
wsgi_app = tornado.wsgi.WSGIContainer(
django.core.handlers.wsgi.WSGIHandler())
tornado_app = tornado.web.Application(
[
('/hello-tornado', HelloHandler),
('.*', tornado.web.FallbackHandler, dict(fallback=wsgi_app)),
])
server = tornado.httpserver.HTTPServer(tornado_app)
server.listen(options.port)
tornado.ioloop.IOLoop.instance().start()
if __name__ == '__main__':
main()
当我尝试设置Python的路径时,我输入了:
export PYTHONPATH=DJANGO_SETTINGS_MODULE=myproject.settings myproject/tornado_main.py
但是我得到了这个错误:
-bash: export: `myproject/tornado_main.py': not a valid identifier
请问我该如何用上面提到的PYTHONPATH来运行这个文件呢?谢谢!
1 个回答
0
不要使用 export
,直接在命令行中按照写的方式运行就可以了:
PYTHONPATH=. DJANGO_SETTINGS_MODULE=testsite.settings testsite/tornado_main.py
这样会用修改过的环境变量来运行 tornado_main.py
。你也可以这样做:
export PYTHONPATH=.
export DJANGO_SETTINGS_MODULE=testsite.settings
testsite/tornado_main.py
如果你希望对 PYTHONPATH
和 DJANGO_SETTINGS_MODULE
的更改影响你从那个终端启动的所有进程。
补充:
dan@dantop2:~/code/django-tornado-demo$ ls
testsite
dan@dantop2:~/code/django-tornado-demo$ ls testsite/
__init__.py manage.py settings.py tornado_main.py urls.py views.py
dan@dantop2:~/code/django-tornado-demo$ PYTHONPATH=. DJANGO_SETTINGS_MODULE=testsite.settings testsite/tornado_main.py
<server starts running>