如何在Scrapy中解析通过xpath提取的其他URL?
我正在根据一个类似索引的页面生成一个项目列表。我有一个起始网址和一系列要遵循的xpath规则:
def parse(self,response):
sel = Selector(response)
sites = sel.xpath('//tbody/tr')
items = []
for site in sites:
item = EvolutionmItem()
item['title'] = site.xpath('td/div[not(contains(., "Sticky:") or contains(.,"ANNOUNCEMENT"))]/a[contains(@id,"thread_title")]/text()').extract()
item['url'] = site.xpath('td[contains(@id,"threadtitle")]/div/a[contains(@href,"http://forums.evolutionm.net/sale-engine-drivetrain-power/")]/@href').extract()
item['poster'] = site.xpath('td[contains(@id,"threadtitle")]/div[@class="smallfont"]/span/text()').extract()
item['status'] = site.xpath('td[contains(@id,"threadtitle")]/div/span[contains(@class,"highlight")]').extract()
items.append(item)
return items
这段代码没有错误,能准确提取我需要的内容。现在我想访问每个网址,并从这些网址中提取更多数据。
有什么好的方法可以做到这一点吗?我似乎无法让request.meta正常工作。
编辑
Girish的解决方案是正确的,但为了让它正常工作,我必须确保我的 item['url']
不是空的:
for site in sites:
item = EvolutionmItem()
...
if item['url']:
yield Request(item['url'][0],meta={'item':item},callback=self.thread_parse)
1 个回答
2
你需要创建一个请求对象,这个对象需要包含网址、元数据和回调函数这几个参数。
def parse(self,response):
sel = Selector(response)
sites = sel.xpath('//tbody/tr')
for site in sites:
item = EvolutionmItem()
item['title'] = site.xpath('td/div[not(contains(., "Sticky:") or contains(.,"ANNOUNCEMENT"))]/a[contains(@id,"thread_title")]/text()').extract()
item['url'] = u''. join( site.xpath('td[contains(@id,"threadtitle")]/div/a[contains(@href,"http://forums.evolutionm.net/sale-engine-drivetrain-power/")]/@href').extract())
item['poster'] = site.xpath('td[contains(@id,"threadtitle")]/div[@class="smallfont"]/span/text()').extract()
item['status'] = site.xpath('td[contains(@id,"threadtitle")]/div/span[contains(@class,"highlight")]').extract()
yield Request(url = item['url'], meta = {'item': item}, callback=self.parse_additional_info)
def parse_additional_info(self, response):
#extract additional info
yield item