爬取URL文件以获取重定向后的最终目标URL？

Question

我有一个文本文件，内容如下：

http://url.com/r/GFDGDFG
http://url.com/r/A32512F
http://url.com/r/AWDRE25
http://url.com/r/AGBFD35
http://url.com/r/NFG4622

有没有办法用Python（我想在我的Linux电脑上写个简单的脚本）来访问每个网址（加载它）并获取最终的网址？每个网址都是一个重定向，我想要的是重定向后的网址。

Answer 1

import requests

urls = '''http://url.com/r/GFDGDFG
http://url.com/r/A32512F
http://url.com/r/AWDRE25
http://url.com/r/AGBFD35
http://url.com/r/NFG4622'''

for x in urls.splitlines():
    r = requests.get(x)
    print x, '=>', r.url

http://url.com/r/GFDGDFG => http://lyrics.url.com
http://url.com/r/A32512F => http://lyrics.url.com
http://url.com/r/AWDRE25 => http://lyrics.url.com
http://url.com/r/AGBFD35 => http://lyrics.url.com
http://url.com/r/NFG4622 => http://lyrics.url.com

结果：